# SolSec7.6 - Problems and Solutions Section 7.6 (7.25-7.31)...

This preview shows pages 1–3. Sign up to view the full content.

Problems and Solutions Section 7.6 (7.25-7.31) 7.25 Referring to Section 5.4 and Window 5.3, calculate the receptance matrix of equation (7.25) for the following two-degree-of-freedom system, without using the system’s mode shapes. 20 01 31 11 62 22 0 1 2 1 2 1 2 0 + + = ˙˙ ˙ sin x x x x x x f t ω Solution: 1 0 0 + + = ˙ sin( ) xx x ft αω () ( ) =− + KMC 21 j ωω () = −+ + +− + 1 26 2 3 2 2 jj ∆= + + − + 28 58 42 3 j

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
7.26 Repeat Problem 7.25 using the undamped mode shapes. Note that the system has proportional damping since C = α M + β K , where α = 0, α = 1/2. Use this result and the result of Problem 7.25 to verify equation (7.33). Solution: For the system 20 01 31 11 62 22 1 0 0 + +
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 02/11/2010 for the course MECHANICAL ms316 taught by Professor Abduljaba during the Spring '09 term at Kalamazoo.

### Page1 / 6

SolSec7.6 - Problems and Solutions Section 7.6 (7.25-7.31)...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online