N261H2 - i g (t) = u(t) A]. i g (t) v(t) + _ 1 5 F 4 1 H...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
EGR 261 Due date: ______________________ Signals and Systems (See Due Dates Table) File: N261H2 Homework Assignment #2 Reading Assignment : Ch. 13, Sect. 1-5, 7 in Electric Circuits,8 th Edition by Nilsson Ch. 4, Sect. 4 in nd Ed . by Lathi Handout: Laplace Transform Properties and Common Laplace Transform Pairs Lecture notes Problem Assignment : 1) Work the following problems from Ch. 13 of Electric Circuits, 8 th Edition by Nilsson: 9, 10, 13, 27(a & c only), 44, 49, 55a, 69a (find H(s) then the impulse response, h(t)) 2) Use Laplace transforms to solve problem 7.81 of Electric Circuits,8 th Edition by Nilsson. 3) Work problem 4.4-7 in nd Ed . by Lathi: 4) A) Determine the transfer function H(s) = V(s)/I g (s) for the circuit shown below. B) Determine the impulse response [i.e., find v(t) if i g (t) = δ (t) A]. C) Determine the unit step response [i.e., find v(t) if
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: i g (t) = u(t) A]. i g (t) v(t) + _ 1 5 F 4 1 H Selected Answers : 13.13) a) i L (0-) = 5A, v C (0-) =150V b) V o (s) = -50/(s + 20,000) c) v o (t) = -50e-20,000t u(t) V 13.17) v o (t) = [-45te-5t + 24e-5t ]u(t) V 13.44) v o (t) = e-10,000t cos(20,000t +90 )u(t) V = -e-10,000t sin(20,000t)u(t) V 13.51) a) 6 2 10 125 + 10,000s + s 15,625s-= H(s) b) z 1 = 0, p 1 = -5000 + j10000, p 2 = -5000 j10000 13.55a) 7 2 g o 10 + 2000s + s 2000s = ) ( I ) ( I = H(s) s s 13.69) a) 1 + s 0.2 = H(s) , h(t) = 0.2e-t u(t) 7.81) v o (t) = 40e-100t u(t) 40e-100(t - 0.006) u(t - 0.006) V 4.4-7) y(t) = e-2t [1.5cos(3t) 5/6sin(3t)]u(t) V = 1.716e-2t cos(3t + 29.1 )u(t) V 3) a) H(s) = V(s) I = 5s + 20 s + 4s + 5 g 2 ( ) s b) v(t) = h(t) = e-2t [5cost + 10sint]u(t) V c) v(t) = 4 - e-2t [4cost + 3sint]u(t) V...
View Full Document

Ask a homework question - tutors are online