calc2 - and (2,−2, 3) are parallel to the plane. Hence...

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whose equations are: L 1 : 8< : x = t y = 2 − t z = 3 , L 2 : 8< : x = −1 + 2t y = 3 − 2t z = 3t. Solution. Since the plane contains the two lines, their direction vectors (1,−1, 0)
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Unformatted text preview: and (2,−2, 3) are parallel to the plane. Hence their cross product will be a normal vector. n =...
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This note was uploaded on 02/11/2010 for the course MA 141 taught by Professor Zeck during the Spring '10 term at Quebec Trois-Rivieres.

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