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Unformatted text preview: 0 = 1, since it is a continuous function of x and y, while the denominator approaches 0 and is always positive. Thus the ratio approaches +1. 1...
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This note was uploaded on 02/11/2010 for the course MA 141 taught by Professor Zeck during the Spring '10 term at Quebec TroisRivieres.
 Spring '10
 zeck
 Math, Limits

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