calc10 - x!0 2 cos(2x 1 = 2 using l’Hospital’s rule for...

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using l’Hospital’s rule for the second equality. If (x, y) approaches (0, 0) along the line y = x instead, we get lim (x, y) ! (0, 0) y = s sin(x + y) 2x − y = lim x!0 sin(2x) x = lim
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Unformatted text preview: x!0 2 cos(2x) 1 = 2, using l’Hospital’s rule for the second equality. Since we get different limits depending on the direction from which we approach (0, 0), the limit does not exist....
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This note was uploaded on 02/11/2010 for the course MA 141 taught by Professor Zeck during the Spring '10 term at Quebec Trois-Rivieres.

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