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# calc12 - = 0.14 −0.07 Here we have taken dx 1 = −1.01...

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Approximate y( 1.01, 2.02). Solution. Let _y = y( 1.01, 2.02) y( 1, 2). We know that dy at ( 1, 2) approximates _y, so we have _y _ dy| ( 1,2) = y x | ( 1,2) dx = _ 6 4 5 1 __ 0.01 0.02 _ = _ 0.14
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Unformatted text preview: _ = _ 0.14 −0.07 _ . Here we have taken dx 1 = −1.01 − −1 = −0.01 and dx 2 = 2.02 − 2 = 0.02. Thus y(−1.01, 2.02) = y(−1, 2) + _y _ (7,−3) + (0.14,−0.07) = (7.14,−3.07)....
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