Calc12 - = 0.14 −0.07 Here we have taken dx 1 = −1.01 − −1 = −0.01 and dx 2 = 2.02 − 2 = 0.02 Thus y(−1.01 2.02 = y(−1

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Approximate y(−1.01, 2.02). Solution. Let _y = y(−1.01, 2.02) − y(−1, 2). We know that dy at (−1, 2) approximates _y, so we have _y _ dy| (−1,2) = y x | (−1,2) dx = _ −6 4 5 −1 __ −0.01 0.02
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Unformatted text preview: _ = _ 0.14 −0.07 _ . Here we have taken dx 1 = −1.01 − −1 = −0.01 and dx 2 = 2.02 − 2 = 0.02. Thus y(−1.01, 2.02) = y(−1, 2) + _y _ (7,−3) + (0.14,−0.07) = (7.14,−3.07)....
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This note was uploaded on 02/11/2010 for the course MA 141 taught by Professor Zeck during the Spring '10 term at Quebec Trois-Rivieres.

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