calc14 - y 1 y 2 y 2 2 2y 1 y 2 + 2y 2 3 4y 2 y 3 _0 @...

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of the composition z _ y as a product of two matrices (do not evaluate this product). Solution. The chain rule says z x = z y y x . So z x = _ y 2 y 3 y 1 y 3
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Unformatted text preview: y 1 y 2 y 2 2 2y 1 y 2 + 2y 2 3 4y 2 y 3 _0 @ −_x 2 sin(_x 1 ) cos(_x 1 ) _x 2 cos(_x 1 ) sin(_x 1 ) 2x1 x21 +x22 2x2 x21 +x22 1 A....
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This note was uploaded on 02/11/2010 for the course MA 141 taught by Professor Zeck during the Spring '10 term at Quebec Trois-Rivieres.

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