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zenerdiodenotesa

# zenerdiodenotesa - T he 6.3V Zeaer diode in the circuit of...

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Unformatted text preview: T he 6.3V Zeaer diode in the circuit of Fig. 3.23(a) is speciﬁed to have V2 = 6.83“" at I2 = 5 m, r: = 20 Q? and 12K = 0.2 mA, The supply voltage V" is nominally 10 V but can vary by :1 V, HGURE 3.23 (a) Circuit for Example _. . equivalent circuit mcdeL (3) Find V0 with no load and with W” at its nominal value. ' _ W . cit '(b) Find. the change in V0 resulting fmm the :l—V change in 'V+, Note that (AVG/AVE usually ' j: 2 i V“ ..._ Va as expressed in mV/Vj is known as line regulation. _ . MWQW gig; m - .(c) Find the change in V5 resulting from connecting a lead resistance RL that draws a current IL 3 - fig: l m? and hence find the load 'regulaticn (AVG/53%) in mV/Im’i‘h - I - : ii: ‘ﬁwi (d) Find the change in V0 when RL 2 21:9. . ' 5943 + l “‘1' (e) Find the value cf V0 when. an: 0.5 kg. ' __ 6 33 i ' , i. a .- _ . . . ..... ~ is ' -' (f) VVhﬂt 3-5 the] minimum value if R}; f0? Wthh £116 dlﬂdﬁ Still Operatas in the bfﬂﬂdeWﬂ region? = “WWW—«Sim 1V: “I \‘f A” HEW rage m fed" a»? “1%“ g 3 3* Q {£3 a) in”? Jam _ 6 r" :3, athy/l ‘3 "“ Ema “a? E m “:3" * 2 ‘Qﬁ ““5 "' “633 M + .. i3 Ava} “—1 AV 2? ., : ii 23 ,_ miggﬁg has] Ed“ TE 3 cam “if“ 2 ‘3 t g t it cf: i maﬁa g; gage-taafwyw w a i) J :: H- I: ‘W 5"” i \f 2:: g; .3; . 3 2m :9“ H m h a h“ a” at: if; e E g " T“ {at x t- 3”? 1L3 3 1 m Pb } :5? m Léfaiiéﬁtﬁﬂeﬁf 4-17} {gut E ‘1} “e E I: E F *5.ng {Ema PM at a. *‘ H h mum “ch ““3. ﬁrst; 2; Vania [MCYWJW Wig}: 2D giuiinwlm‘aaahf m . _ . F" G 13-3 2% “Ti f‘a F13 t a; an i: ”i I D 35 \ l>~ H I” [E l M 0 “53:... wt! 5 “D it“ I M O t?» €11 “:e i I} r “*“L F " “t“ “" “”ﬁ 1 . ﬁt”: I?” 94+ -:.-'I:'. K 5:3 RE; lye-g Ea we? ﬂ IE "3. amai {‘3 a; am hi F :E in: ﬁg; in? 1' V; a! E W 6 g} “P?“ V 1.5a? 3:.“ aim- j + m: ,,_, 5:, a m J: 4 pf ,.... m, :3 f} i a ; a. i m .L gag ._..,, 0 cm. L: u; aﬂeﬁ» --~ I :é We; :17 m “be; pace-wade ...
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