# CHAPTER - . If you stack identical cubes side by side and...

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CHAPTER #23: QUESTIONS: PROBLEMS: •1 The square surface shown in Figure 23-26 measures 3.2 mm on each side. It is immersed in a uniform electric field with magnitude E = 1800 N/ C and with field lines at an angle of θ = 35° with a normal to the surface, as shown. Take that normal to be directed “outward,” as though the surface were one face of a box. Calculate the electric flux through the surface. 1. The vector area and the electric field are shown on the diagram to the right. The angle between them is , so the electric flux through the area is . ••11 A particle of charge + q is placed at one corner of a Gaussian cube. What multiple of q /e 0 gives the flux through (a) each cube face forming that corner and (b) each of the other cube faces?

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11. The total flux through any surface that completely surrounds the point particle is
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Unformatted text preview: . If you stack identical cubes side by side and directly on top of each other, you will find that eight cubes meet at any corner. Thus one-eighth of the field lines emanating from the point particle pass through a cube with a corner at the charge and the total flux through the surface of such a cube is . (a) Now the field lines are radial, so at each of the three cube faces that meet at the particle the lines are parallel to the face and the flux through the face is zero. (b) The fluxes through each of the other three faces are the same, so the flux through each of them is one-third the total. That is, the flux through each of these faces is ....
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## This note was uploaded on 02/12/2010 for the course PH 211 taught by Professor Herzenski during the Spring '10 term at Boston Conservatory.

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CHAPTER - . If you stack identical cubes side by side and...

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