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5 Solution - \. mg 37% ’“omexoerm £5 1 Hidoflkm an...

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Unformatted text preview: \. mg 37% ’“omexoerm £5 1 Hidoflkm an \Ha Assume: MM PM figs 1 JM-lo heigfififia mme ‘ D4Qah 02: LDXtDI-S a}? + 6"“ Am -—-——:‘> Tin—HOOK; / M E \ Tm a 50°C, Jngaobrfil kaomn E E z 1% {"95 I ’5’"): ; MRGO-(m Liam, JUNO Sfloxm S I To "‘ LkDDaC Tm“ Sbic “kc aDDfi.L { ' l i R ’9) 2L5 . 1 L5" *5 ' r+LLs fjma (905 Pmblcm. X“: 4”” “WOMX m3? _. l h- o a 9.; Tm, : 1:59 a T” SD fifi-Tu) LfDD~ 51> (a) Cemer Whperaqu/c 1w 5 50 + (0.965%) 11%; Ware 5 A Harm—live. Mefikoob Vgecausc rec:me Q Vafll’u IVS KXYDD $Nm . @ \U-Ltok t5 m4: Wino acceof‘oufic, Ul$c E06. u. LKLOd : 8x0 = A1 {WP VORR XE) ‘me Vi?) LUNCH A. a ma ’)\ fia‘O-q ==> ’h =o.9 8.” £1.19 wg(0.q)a( 1.31)] = 0%39 Tam; “ 50 + (Ofitake) (356) Sur—Cace irempemficwm/ Ymm Y3 Ill-W6 9}. .. ' Ob 8'0 "' 00$ at -—- 0.3 9: ~ SN,“ {Pa‘g-{Q‘KQ ngSOoL‘ 5‘ = 0.940%) = 033 TM“: 50 + 0.736%) lué‘aa: Ymh ParJDOq \‘E 8‘0 =O' Maw 65’, =~ 03(049‘0 ‘* 0&3? 1mm = 50+©33®Q 350) TMM = WOVC, (C3 T0 QQRMCUER 0‘ mac equafldm-Qmm dons g __ ___ ,, JIM) ka.“ ‘\ a9' 7‘ I “am M‘déherw Via 15K»! JKOH) = 0-H Q 7 *Q—mk == 1- Q ( OH X050 um} QM’IUDV (TN—Ta) = % V (Tm—Th) : 0. (EN .52 Cu 11 n Cali? Luv—“i- : O . (9Lka m-Lc. mow Q mm 040W ’fgv L 110—1) Lem-5 3;: [mo-"QB (a mi) (SfiC‘LtOD’ C ) 7—5‘b1X‘07 W~5 x m'z’ 5);? L5. QM?) mm w X 5500 s rxe Jr'wc shamindequ Mai “5 “905*- wmafifinobz/r‘l'b WW Asfimz conchouch ?mpc(fi€5 (m Mfiugibflz raovwflm Ta, ab‘C b , ‘ w =LtooC : Mmmz $1 “A "(a Virch Gaga/Jake: w 15L = ‘m; \0 m, (5 xxo'3m) = u——.__"' -_ K aO—“i m-K Sb %1 (<1, Cmd we can use humped cafid'fance meoflsz 8 gT~ To c "535% ~ao'c E ' To ~Tq HDD‘C—éIO’C a (9.53453 DU): [0 Uo) 5pké’xc cooled Qor +1me in meflrfi‘srrfofl bocfh TN = 80°C , JPN-flows “E; (H h], To = 50°C Unifiafl T is 355°C) Yam w Shwfocew Pm magma . w -3 151': J55”; LDOO $526210 m) K 30 fig 5 [-5 NOW 1% ' M 1,313, [{ us: @Remoofim Heehod 1cm” Qwfin$ ngi we 2% u.qu a 8: A! fim'h‘i 733 A‘L (MN—\cr f€=0 5\h )13 '__ 2'“ fig -3 +or g=o 8; 2 A! Q’fipC—fha X‘Fu) FD? 1:16; Viva lllS’Q A:*1=Lf5 ?~ “ -‘- = 0.. b — 7} = ’V'ibi, 8 Q 80 = LUr’S efim’mah) :2 exp (J)! 2 , a 0% (“END 3 M) o< 30%“ 3000 Eng; c I000 t» 3.19 K XV 0.8% g :LTsm£_Tw)/(.T0'Tw) 7: 0:6 Um .~ Tu, MTG - Tm) '— tswgm ,_. Tua + 0.5 (Tami-er ’71)) : 90°C +0.5 (son—cab?) \T‘BWLL c / // 1L%’£O)c&50: stme‘ HI: ‘8 5Uva(oof1n W saw Mr +‘t5 WM Mm wwwcmm wc’mgoomp hm cu Wfisfiiw $S’CPJ _ exp/(1W c9N~oUn~wk9m£ {mafia/a? comm/95M VNQd-Hcsr JL —. 0.15 :7 q ,= $5 : OASKTL _IOOHD_7 ma 0DCP». \.”3¥/D‘>Nfi J’ P Lambs: ' s Ck—\ Tse {‘0 Tx = 35°C Mkee‘txrc WM SGQW SWCRC/‘LCIVU‘U WOW->6 500C ‘b‘ D CdWQ W“ (o) Agom hybng M—e we 2 will mum 4am: meme (30%? Er SW-‘mfinpce sefid 9 = fir? TL T. T’ 22L. TL’TS a4 T0 fiefi +b 55°C SD'Q— EDT, 0 00‘! m &5°C- [50°C : er( &(1.oox167">;- [QC/2) TQ us: 030d swt ‘m EKCe/Q 4% Ruck ’X 3% ‘Wcfi €14 'x=0.%b, ’ %= 0.9% Kama-us: M\&0Qteman Vi?) Boll! bui rx ,Mhs cmweeas JAM O.%,\ok\o\1\is %%m Ah 00%qu VaQ/wz) mas EV" = 0- 90" J: c L555) SCC = 0.8} mm 3hr\iw~-‘rb-.ng+~\’l\c is m 0.3: mm 2955‘ mm “may: 59%! NR,$\Q,Q0\+Q Calf/dim T: %(0°Q/ $155ng (if Q.8l "\‘m 31%: ‘15 .QQMHC‘A laO°Cl WWW— wtu wt mum. (LA 9%! m1“) = ‘9 (0'35‘fn33(as°c- max =i‘5b K)! 1.6 xw‘fiQJSAgfiQBIMX W £929 law» 35 ...
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5 Solution - \. mg 37% ’“omexoerm £5 1 Hidoflkm an...

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