# HW16 - PROBLEM 6.3 Using the method ofjoin‘ls, determme...

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Unformatted text preview: PROBLEM 6.3 Using the method ofjoin‘ls, determme the force in each member of the was shown. State whether each member is in tension or eompremion. 80LU110N - mm Truss: (m, = o: (ﬁﬁ)(6kips) ~(9 Inc, = o c, = 4595] 1m=o:sy—6hps—c,-o B,=101dpsT -«- 2F,=o:c,'=o Fm =7.5Dk:ipe Ci Byinspeclim: FAB s12.50 kips C ‘ PROBLEM 6.10 Determine the force in each her of the Howe roof truss shown-1. 30LUTIUH FBI} Truss: Fm=lznokNT4 Fm =15.ookN c4 so Fm =15.DOkN C4 F65 =12.00kN T“ F36 =0=Fm‘ 53:12.00de Fm=1zmm T1 so since =03 so sin}? \$0.96 \EFy1=0:—6stina+FMsinﬁ=0 J Fﬂ=smmci PROBLEM 6.10 CONTINUED ‘ 'éFﬁ-gﬁmhgﬂsmysm FED-10.00%! c 4 so FN=10.001:N C4 1m=o:—6m+2[%1oku]-Fm =0 Fm = 5.0013»: T4 PROBLEM 5.23 ' C mt = 0‘ (10 "=09; - (7-5 m)(80 kN) — (8 m)(3o m). = u Gy=s4kNT ..I ..;T‘EFx-02—Fx+3okN=o Fx:30kN_._ au- _. T Iggy—‘9:F,+s4kN—som=o Fy=4m1 ByinspectionosfjuintG: _-Fm=o‘ Fm=84kN 04 FE =82.0kN T4 _ Fm =56.Sl:N :14 W» ' - 2.- 6 TEF,=0:7s-Fﬂ+76—l(82.0kN)-80kN=0 32.0fm“ as - 19.01312 FE =19.u1kN T i _ - —. 21;; 0: 47m — 71509913 kN) + 7%(323 kN) = o Fm=43.99kN Fm-M.0kNT4 Fm =6'mkN T4 PROBLEM 6.23 GOHTINUED- 2 [2:13 =ﬂ:7§r(67.082kN)—F3F—4kﬁ=0 F5,— = 56.0019; 5,, =' 56.0 kN c 4 5 5 —.-. = z - _ = - 6 3 __ z _ F _ F — 0 ﬁlm] T 51 3.0 7—29 A: 0 F» = 42.5mm F» = 43.0kN T 1 Fu=61929kN _Fﬂ=51.9kN c4 _ 6 2 _ = T 2!; _ 0. Emma N) + Us—(Fm 67.082 N) o FAD = 30.151!qu FAD - 30.2}! T ‘ ...
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## This note was uploaded on 02/12/2010 for the course EGM 2511 taught by Professor Jenkins during the Spring '08 term at University of Florida.

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HW16 - PROBLEM 6.3 Using the method ofjoin‘ls, determme...

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