HW32 - PROBLEM 10.17 Derive an acpression for the...

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Unformatted text preview: PROBLEM 10.17 Derive an acpression for the magrfitude of the couple M required to Virtual Work: WHO: Him—Pit, -0 M59 — Pamela‘s) + P(-:sinaaa) _= o M g Pl[sin0 + mafi)‘ PROBLEM 10.20 Amupchofmaguitude 751b'fi is appfiedasshowntotheerankof the engine system. Knowing that 13:25:31. and BC=10in., demfinetheforeePrequiredtomaintaintheequilibflumofthcsystum when (a) «9 = 60°, (5) 9 =120°. SOLUTION From the analysis of Problem 10.19, Now. with M n 7511341 = 900 lb-in. (a) For 9 = 60° P = 363.5 II: P=3691b—-d (b) For 9 = 120° sins = fismzm, s =12.5o4° 5511020“ +12.504° (900 lb-in.) = (2.5 in.) “125040 Jun) or P = 476.71]: PROBLEM 10.30 NomdsACandCEmcnmactedbyapinatCandbyaspingAE.The constatoffiespflnghSflflN/mandflwsprhgisunstrflchedwhan 9 = 30°. me'ingfllatl: 200mm andnnglecfingfincmassofflierods, detcnninethevalueofe oorrespmdingtoeqlfillibfiumwhanP =160N. SOLUTION Fromflw analysis of Problem 10.29, $ _ 1 2:15:10 mmwm‘ P=150N,z=o_2m_mdk=3mmm 166 N = 1 — 2 sim? 3(300 N/m)(0.2 1.1) my I — zsimsl 1 — = — = 0.3333 m- tanfl 3 Solving numerically, a =24~98° o=zs.n°< ...
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HW32 - PROBLEM 10.17 Derive an acpression for the...

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