HW33 - PROBLEM 10-59 Using the method of Suction {0.8,...

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Unformatted text preview: PROBLEM 10-59 Using the method of Suction {0.8, solve Problem 10.29. Spring: AB = x = 2(2Isin9) - 4Zsln9 Unmatched length: x. = «mm = 21 Dcflccliomofspring S =I-Iu s=21{2§infl'—1) V=%h2+Pyg r = %k[21(23in0 - 1)]2 + P(—lcos€) % = 4320:1116 —1)2cos6 +Hsina = o . 13056 P PROBLEM 10.61 Using the method of Section 10.3, solve: Problem 10.31. SOLUTION AE = x = 2(2Isina) = 415in0 x9 = 413ln30° = 2: s-x—fi s = 21(2sin9—1) V=-;-h2+lyc 1 _ 2 = Ek[21(23m9 - 1)] + Pumas) Y = 2H=(2sino — 1)2 + Ploosfl a = “33055113 — 02qu - PlainB = o . m8 F 1—2 .— —= ( ma)sin6+w o L: mine-1 8H tans PROBLEM 10.51 CONTINUED P=160N,l=200mm, and k=3mNIm (16011} ' ' a ZflnQ—l 3(300 me)(0.2 m) we I 25in€-1= H = 39.65“ PROBLEM 10.87 - .Showrmme eqxfilibriumis neutral ianhlem 10.1. y1=fl yD=—4.5u I)’G=3-5“ V = (300 N)” + (100 N)» + PM} = 0 F = 300:: +100(—4.5u]+ P(2.Su) = 0 V = [—150 + 2.5P)u %-—150+2.5P=Dsothat P=GDN SubstimteP = so Nin expmssion for V: r _= [—150 + 2.5(60)]u =0 Visoonslnntand Bquih‘briumianmtml4 PROBLEM 10.74 In Problem 10.40, determine whether each nfthe positions ofeqtfllibrlum is stable, unstable, afncuiral. (See the hint for Problem 10.73.) SOLUTION Potential Enflrgy V a in“ —Plsin9 g- - K9 L House - d2? ' — = K + mine as” E =137333 rad, 5.652 rad, and 6.616 [lid 9 = 78.7", 323.8", 379.1" fl: do” - 1179.6 ft-lb } 0 9 = 78.7°, Stable " StabflityAt 9 = 78.7”: (-150 Emma) {- (12601b)[% anmsr d’r At a = 323.3°: —— . 3.92 =(1501b-Mad) +(1260 Ib)[% fi]sin323.8° -_— 47011.11, 4 o 9 = 324°, Unstable! At' a = 379.1°: % = (150 mm) + (1260 MG—g— fijlinSTS'. 1° - 493511-111 > 0 PROBLEM 10.75 ' Angle a is equalto45° afiarablockofmassm ishung fi-ummemberAB asshovm.NeglecfingmemassofABandlmuwingthatfl1espringis umiretchcdwhen 6:20“, determinethcwlucofmmdstatewhethur the is stabln, unstable, or nqun'nl. Have V=~§hip+mgr3 where rm. =.r(9—9,), :- =1ogm go a 200 -1; m y, - Lame. La :- 450mm V =% hr: [9'-— an? +-mgaLA, c056 _ 2' __ I _ . do“ k=soonm 9:4? *1“: ‘MLflmg :3; = a: (son Nhn)(0.l m)2[% - — m(9.31m/s:)(0.45m)sin% = o m=1.11825kg m=1.118kg4 5% = (800 1~Mm)(o.1m}2 — (1.118 kg)(9.81m!sz](0.45 m)ous% =4.51I > I} PROBLEM 10.92 Twnbmareaflxhedloasingleslringofconmmkflmismtched when the bars are vertical. Determine the range of values of? for which the. equilibrium ofihe system is. stable in the position shown. Spring: 3 = %sin¢ =-%sin9 _Forsmallvaiuesuf¢md0t ¢=26| V = P[£eus¢ + Ems] + 11-31 ., .3. _ 3 2 2 = %£(e0529 + hose) + %k[%sin9] .% = £3L-(-Zsin?fl — Zshfl) + %kL=sin9msa i“ _= -_%[23i1129 + 23in0)+%kfisin120 2 fl = _£(4ms26 + 20030) + ikLzeosiZfl 9'02 3 9 z 9=u: flhflfi __2 as: 3 9”“ ...
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This note was uploaded on 02/12/2010 for the course EGM 2511 taught by Professor Jenkins during the Spring '08 term at University of Florida.

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HW33 - PROBLEM 10-59 Using the method of Suction {0.8,...

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