15.1Ex50-53

15.1Ex50-53 - 622 C H A P T E R 15 D I F F E R E N T I AT I...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
622 CHAPTER 15 DIFFERENTIATION IN SEVERAL VARIABLES (ET CHAPTER 14) 50. Find the change in elevation from A and B . SOLUTION The segment AB spans 7 level curves and the contour interval is 10 meters. Therefore, the change in elevation from A to B is 10 · 7 = 70 m. 51. Estimate the average ROC from A and B and from A to C . The change in elevation from A to B is 70 m. The scale shows that is approximately 1500 m. Therefore, Average ROC from A to B = 70 1500 0 . 047 . The change in elevation from A to C is obtained by multiplying the number of level curves between A and C , which is 8, by the contour interval 10 meters, giving 8 · 10 = 80 m. Using the scale, we approximate the distance AC by 3500 km. Therefore, Average ROC from A to C = 80 3500 0 . 023 . 52. Estimate the average ROC from P to points i, ii, iii, and iv. The points i, ii, and iii are on a level curve adjacent to the level curve of P , hence the change in elevation is 10 meters. Using the scale we approximate the distances from P to the points i, ii, and iii: From P to i: 400 m From P to ii: 400 m From P to iii: 640 m Therefore, Average ROC from
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online