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Unformatted text preview: C = | W | | Q h | = | Q h | | Q l | | Q h | = T h T l T h Solving for heat going to the cold reservoir: Q l = | Q h | | Q h | C = | Q h | (1 C ) Substituting in values: Q l = (2500 J )(1 . 25) = 0 . 75 (2500 J ) inally: Q l = 1875 J (b) How much work can be done with this engine? Again, using the equation for eFciency of a Carnot engine, one can solve for the work accomplished: W = C | Q h | = 0 . 25 (2500 J ) inally: W = 625 J (c) What is the change in entropy oF the process? A Carnot is a closed cycle process, i.e. it begins and ends at the same point. As such, the change in entropy must be zero for the entire system. Stated dierently, the change in entropy in the hot reservoir must equal the change in entropy in the low temperature reservoir: | Q h | T h = | Q l | T l inally: S = 0 J/K 2...
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- Spring '10
- Second Law Of Thermodynamics