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Unformatted text preview: the fulcrum. If we imagine that all of the stick's mass is concentrated there, we'll have an identical problem from a physics standpoint, and it is one we can solve: T = F x R T total = 0 T total = T rock + T stick's Center of Mass T total = (M rock G) x (-1 m) + (M stick G) x (1 m) = 0 M rock = M stick = 30 kg 3)If the person's usual weight on Earth is 600 N, then by F = MA, F = M A 600 N = M (10 m/s^2) M = 60 kg Now, using F = MA again with A = 26.7 m/s^2 for Jupiter, F = (60 kg) (26.7 m/s^2) = 1602 Newtons...
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This note was uploaded on 02/13/2010 for the course PHY 303L taught by Professor Turner during the Spring '08 term at University of Texas at Austin.
- Spring '08