Mid Term Test 2 2004 Solutions

Mid Term Test 2 2004 Solutions - Materials 1M03, Test #2...

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Materials 1M03, Test #2 2004 Version #1 Last Name:_____________________________ First Name: ______________________ Student ID#: _________________________ Tutorial Section:_____________________ MATERIALS 1M03 TERM TEST #2, 2004 This test contains 6 pages and 14 questions. You are responsible for ensuring that your copy of the paper is complete. Bring any discrepancy to the attention of your invigilator. A 1 2 3 4 Total SPECIAL INSTRUCTIONS: Aids allowed: 1 page crib sheet, nominally 8½ by 11 in. McMaster standard Casio FX-991 calculator Answer all multiple choice questions on the special answer sheet only. Answer all written questions on the examination copy. Be sure to show your work so that part marks can be awarded for incomplete answers. Be sure to include units with all answers that require them. Marks will be deducted for using an inappropriate number of significant digits in your final answer, but always use a minimum of three significant figures. The value of each question is shown. The total for the exam is 60 marks Useful constants: Gas constant, R = 8.31 J/mol-K Charge per electron, e = 1.6 x 10 -19 C Avogadro’s number, N A = 6.02 x 10 23 Boltzmann’s constant, k = 1.38 x 10 -23 J/atom-K = 8.62 x 10 -5 eV/atom-K Part A: The following multiple choice questions are worth 3 marks each. In each case, put your answers on the scan sheet (marked McMaster University Examination Answer Sheet). Read the Marking Directions on this sheet carefully before starting. 1. Fick’s first law x C D J = describes steady-state diffusion. The term “steady-state” means: a) Diffusion occurs in a solid which not being deformed. b) The concentration at each location in the solid is not changing with time. c) The diffusive flux is proportional to the position x. d) The diffusion coefficient is the same everywhere in the solid. Page 1 of 6
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Materials 1M03, Test #2 2004 Version #1 2. The correct form of Fick’s second law for diffusion is a) 2 2 t C D x C = b) 2 2 x C D t C = c) 2 2 x C J t C = d) 2 2 x C J t C
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This note was uploaded on 02/13/2010 for the course ENGINEERIN 1m03 taught by Professor Porove during the Spring '10 term at McMaster University.

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Mid Term Test 2 2004 Solutions - Materials 1M03, Test #2...

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