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CH8_Page_13 - fl Bah-em xw ———— ”unknown...

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Unformatted text preview: fl _ Bah-em xw ———— ”unknown + ”ml-mu 100' g _ -—1 0,9.” = 46.0?g 11101 100g + 9.15g 46.07g-mol" Mm M F——fl——=lSBg-mol" “W“ F 100 g 46.07 g -mol" _ 100 g 0.9?4 45,07 g 41101" 8.52 (a) The molality of the solution can be calculated, knowing the: flooring point; this value can, in turn, be used to calculate the boiling point. AI; =krm Because the solvent is water with a nonnal framing point of (PC, the fi'oezhlg point of the solution is also the 15.3} . 1.04 K. =1.86 I‘C-kg-n‘ml'1 x molality molality = [3.559 mol - kg" :52}, = khm = 0.51K-kg-n101" 3-: 0.559 tool-kg" = 0.29 K or 029°C boiling point =1flfl.00"C + 029°C =10E|29°C {h} M“. = kg»: {1?} = 55°C — 10°C =3.S°C or 3.5 K 3.5K: 5.12 K-kg-mol" xmolality mobility.r = 0.63 mol -kg'1 A3; = kbm = 2.53 K. -kg- mor‘ >< 0.68 mol-kg'l =15r Korl.7°C boiling point -— 8D.1°C +1.?"C = 813°C 239 ...
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