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CH8_Page_16 - dissociation had taken place the inolslitg.r...

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Unformatted text preview: dissociation had taken place, the inolslitg.r in solution would have equaled 0.124nio1-kg'l. concoonoq) t——* H*{an + CCI3COD'(aq) 0.124niol«kg" —x x x 0.124 molvkg," — x + .r + x = 0.22? mol -kg‘] 0.124 mol Jung" + x = 0.227 mol - kg'1 1: = 0.103 mol- kg" 0.103 tool-kg" 0.124molLkg 9’0 ionization = 8.62 First, calculate the osmotic pressure of each solution from H = SET x molarity . (0] KC! is an ionic compound that dissociates into 2 ions, so 1‘ = 2. I? =2XG.USZU5L'atID‘K_1'mfil-I x 323 Kx I110 nio1+L'I =5.3atm {b} urea, COIfN'Hg): is a nonolson'olyto, so i = l. H = 1 x 0.082 06 L aims" -mol" x 323 K x 0.00 moot" =15.9 atm (o) K1504 is an ionic solid that dissolves in solution to produce 3 ions, so i = 3. H = 3 x 0.032 00 L-aim-K" -inol'1x 323 K x 0.30msl-L-l =24 atm Solution (c) has the highest osmotic pressure. 8.64 Insulin is a nonoleotrolyto, so i = 1. H 2 {RT x molarity H =Lfl= 1x 0.08206LLm-K'1-mol'l TfiflTorrratm [ 0.10 g ] x 293 K): M 0.2001. 242 ...
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