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CH8_Page_17 - M 0.032 00 L-msrl-K'1 ~mol'1 “W" 2.30...

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Unformatted text preview: M _ 0.032 00 L-msrl-K'1 ~mol'1 “W" 2.30 Torr x 0.200 L X 293 Kx 0.10 g x 760 Torhatm'l 2.30Torrx0.200L = 4.0):103 g rmol'I 8.66 We assume the polymer to ho a nonolectrolyto, so a“ = l. H = iRT x molaritgr =—fi'582T—DH—_l=lx0.082 06L-atm-K" -n'lol'I 760Torr-a1m [ 0.50 g ] x 293 K x M - 0.200L 0.082 06 L-atm -K" -mol" 3-: 293 K x Munlowwn :__——— 0.582 Ton- x 0.200 L x 0.50 g x 760 Torr -atm" 0.532 Torr x 0.200 L = 7.0x10‘ g-mol" 3.68 {0} Assume that CfiHIZDfi is a nonolootrolyte, so 1‘ = l. H 2 iii“? >1 molarity =1x 0.002 06 L-atm-K." marl x 293 Kx 3.0 ><10'1 mol- I:L = 0.072 atm {b} (321011 is an ionic «001111300110 11101 will dissolve in solution to give 3 ions, so 1‘ =3. H =1‘RI' x n‘lolsi-itj.r = 3 x 0.032 06 L-atm-K." 41101—1 x 293 EX 2.0 >010"3 11101.1.” = 014 atm (o) K1304 is an ionic oompound that will dissolve into 3 ions in Solution, 1' = 3. H = 1???“ x molarity = 3 >< 0.082 06 L-atm-K" annul—L x 293 K x 0.010mo] -L'1 = 0.72 also 243 ...
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