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CH9_Page_07

# CH9_Page_07 - {h K = Pmlﬂhs = 9.4 x 10—2[1202...

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Unformatted text preview: _.... {h} K = Pmlﬂhs = 9.4 x 10—2 [1202 KY" [12.022 K c ' K— '— {2—H} — 9.4321424 =1.5x1tr“ 292 K 9.23 For the equation written 2 301(3) + 02 {g} —> 2 303 Lg) Eq. 1 2 P30, =—2—= 2.5 >4 1-2” Else: Fin, K {a} For the equation written 303 (g) + ‘5 Oilﬁg} —) 803g] Eq. 2 P Km =P—503—=,HK&_1=14“2.5X10” =1.5><1c-5 1:2 5‘3: P92 (b) For the equatieu Wl'ittﬂﬂ 303\$) —} 301(3} + iﬂz'ig} Eq. 3 1 1 This equation is the reverse oqu. 2, 50 Km; = — 2 Kat-2 Kw go 1% 1:2 1 = = = ——r=ﬁ.3xlﬂ_° 1 K =_-— = E” Pm, .t'KW 2.5 >< 10“" {e} For the equation written 3 302 (g) +% 02 (g) —} 3 803 (g) Eq. 4 This equation is %x Eq. 1, so Km, = KM,” P 3 | K512 : ﬂ =KEq-1M2 : {2‘5 X lﬁlﬂ}}ﬂ = 4.0 X IBIS | so u 1 I 9.30 N2[g)+3 Hglﬁg) = 2NH3{g) K=3.r51t1t}'2 (1} H2113) + Bragg) = 2HBr(g) K= 1.3 x 10‘“ (2) 3 x (2} 4 (1): 2 ﬁll-Mg) + sung) = 142(3) + s HBﬁg} = {1.321019}; ——_2 =s.1x10“ {15:40 ) K for this reaction = (K2? + K. 9.32 Hg(g) + (313(3) —> 2 HCl(g) KC = 5.1 ><1IZIS 263 ...
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