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CH10_Page_26

# CH10_Page_26 - the solution lies between the ﬁrst and...

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Unformatted text preview: the solution lies between the ﬁrst and second ionization, so the predominant species should he the singly,I depletonsted ion H1P04'. 10.96 The equilibria present in the solution are: st(qu + Hzotl} e—_\ H30+{aq} + HS'(aq) K“ = 1.3 x io'T I—IS'{nq} + ngoo} : mount]; + 511m} K” = 1.1 x 10'” The calculation of the desired ooncentrations follows emitted},r after the method derived in Eq. 25, substituting HES for H2033, HS' for HCDE', and st' for oof: First, eeleulete the quantity f [at pH = 9.35[H,o+]=1:::ﬁ*'-t5 = 4.5 x 10“” mol . L'J): f: [H3011 +[HSD+]Kal + Kai Ken = (4.5 x 10'1”)2 + (4.5 x 10'”)(l.3 x in") + (1.3 e 10"}[11 x 10-15;. = 5.9 >< 10'” The ﬁction of the species present are then given by [H301 _ (4.5 x ism}2 = e 3.4 1o" a{HZS} f 5.9}(10—n X o(HS'} = [H30‘1Kul : W = {199 f 5.9 x 10'” -1 -I5- “(Se—}=ﬂ=m =].ﬁ:-< IUZ’ f 5.9x 1o"” Thus, in u solution at pH 9.35, the dominant species will he HS' with a concentration of (0.250 mol - L")({l.99) E 13.25 mol - L"L . The concentration of H23 will be {3.4 x 104;:(0250 Incl - L" J = 3.5 x 10* met - L'j , and the eeneentretien of S:— will be (1.6 x lﬂ'5)(0.25{l mol - L'l) = 4.11} x lﬂ'ﬁ moi - L4. 10.98 For the ﬁrst ionization ofﬂiﬂUHh—or Hgozﬂt—we write HICZDK. + H30 r—‘t HE‘EJI+ + H0204: K] = 5.9 x10" Concentration 321] ...
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