Midterm2_20040

Midterm2_20040 - Exam # _ You can tear this sheet off and...

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Exam # _______ You can tear this sheet off and use it as you wish. Equations for 2 nd Midterm Exam Linear kinematics: avg. v = r / t ∆ ∆ (r = displacement, position) avg. a = v / t (if constant acceleration): v f = v i + at r f - r i = v i t + 0.5 * at 2 (r = displacement, position) v f 2 = v i 2 + 2a(r f - r i ) Angular kinematics: ϖ = •+ α = •+ @ •S ¹ ª * à$׺ r = radius s = r θ ϖ = θ / t v = r ϖ α = ϖ / t (t is tangential): a t = r α (r is radial): if constant acceleration: a r = r ϖ 2 = v 2 / r ϖ f = ϖ i + α t θ f - θ i = ϖ i t + 0.5 * α t 2 ϖ f 2 = ϖ i 2 + 2 α ( θ f - θ i ) Forces (c = centripetal = radial): F c = mr ϖ 2 = mv 2 / r = ma c F t = mr α = ma t F = ma Σ Η {S ¹ª Σ z H{S ¹ª z à$× ºª * á μ? •+ •+ H{S ¹ª * : Σ y H {S ¹ª y – mg otherwise Σ y H {S ¹ ª y maximum F frictional = μ F N (where N = normal) F drag = -0.5 A C D ρ v 2 G (linear momentum) = mv Impulse = F dt = F avg t U (work) = F * d P mech (power) = F * v = U / t Translational kinetic energy: E k,t = 0.5mv 2 Gravitational potential energy: E p,g = mgr y Elastic energy = 0.5k( x) 2 Elastic energy = 0.5 F x joint @ ôD + , flexion is Basic stuff: 2 π radians = 360° 1 radian = 57.3 degrees circumference = 2 π r sin = opp/hyp cos= adj/hyp tan = opp/adj Gravitational acceleration = -9.81 m/s 2 speed = stride length x stride freq. quadratic equation: solutions = -b +/- sqrt( b 2 – 4ac) 2a
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Exam # _______ circle your TA: Chris Krissy Jenny Steve Bubba Midterm Exam #2 Biomechanics IPHY 4540 Fall 2004 Print Name_______________________________________ The exam has 2 questions, each with 4 parts (D,C,B,A). The parts get progressively harder.
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This note was uploaded on 02/15/2010 for the course IPHY 4540 at Colorado.

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Midterm2_20040 - Exam # _ You can tear this sheet off and...

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