# 220F09_Answers-Final - = -10 kip M z = -290 kip-in A =...

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Answer Key for Old Exams – Final Exam Statically Indeterminate Beam Problems : 3 2 1 4 3 3 6 8 1 3 6 6 1 ) ( m kN C x C x x x A EI x y y + + = C 1 = -216 kN-m BC’s: (a) x = 0, y = 0 (b) x = 12, y = 0 (c) x = 12, y’ = 0 C 2 = 0 A y = 24.75 kN D y = 29.25 kN M D = -81 kN-m 1) 2) 3 2 1 4 3 4 2 3 20 48 1 20 6 48 1 2 6 1 ) ( ft kip C x C x x B x x M x A EI x y y A y + + + + = BC’s: (a) x = 0, y = 0 (b) x = 0, y’ = 0 (c) x = 20, y = 0 C 1 = C 2 = 0 A y = 1.75 kip M A = -5 kip-ft B y = 20.25 kip 3) A y = 3.25 kN B y = 8.25 kN C y = 0.5 kN 4) L M A o y 2 = L M B o y 3 = L M C o y = Stress Transformation Problems : 1) σ P1 = 9.66 ksi σ P2 = -13.66 ksi τ S = ± 11.66 ksi σ x’ = 8.194 ksi τ x’y’ = 5.660 ksi 2) σ P1 = 11.30 ksi σ P2 = -9.30 ksi θ P1 = +14.53 ° θ P1 = -75.47 ° τ S = ± 10.30 ksi σ S = 1.00 ksi θ S = -30.47 ° 3) σ P1 = 20 ksi σ P2 = 10 ksi σ P3 = 0 τ max = 10 ksi σ w = 12.5 ksi τ w = 4.33 ksi 4) σ 1 = 144 MPa σ 2 = 72 MPa SF = 1.83 Combined Loading Problems : 1) σ A = 21.37 ksi τ A = 17.50 ksi σ B = -23.81 ksi τ B = 16.90 ksi 2) P x = 30 kip V y
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Unformatted text preview: = -10 kip M z = -290 kip-in A = 0.625 ksi A = 0.313 ksi B = -5.417 ksi B = 0 3) P x = 10 kip V y = 1.25 kip M y = 80 kip-in M z = 20 kip-in T x = 10 kip-in V z =0 A = 3.979 ksi A = 0.796 ksi B = 13.53 ksi B = 0.928 ksi 4) V z = 5 kN T x = 2.5 kN-m M y = -3.75 kN-m P x = V y = M z = 0 ( K ) x = -1.627 MPa ( K ) y = 4.5 MPa K = -1.292 MPa ( L ) x = 2.25 MPa ( L ) z = 4.5 MPa L = 2.455 MPa Buckling Problems : 1) P cr = 38.87 kN T = 46.7 C 2) P max = 11.88 kip = -0.0390 in 3) P max = 8.308 kN 4) P max = 50.28 kip Stress Concentration & Failure Theory Problems : 1) P max = 19.61 kN hole governs design 2) P max = 26.77 kN hole governs design 3) P1 = 32.51 ksi P2 = -8.655 ksi S.F. = 2.235 4) = 18.77 P = 11.73 P P = 3.615 kip...
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## This note was uploaded on 02/15/2010 for the course ENES 220 taught by Professor Staff during the Spring '04 term at Maryland.

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