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ECE35 WIN10 Midterm Solutions

ECE35 WIN10 Midterm Solutions - Lari-9r n It(mid-Lav...

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Unformatted text preview: \* Lari-9r; n It; (mid-Lav...) University of Califomr‘a San Diego Department of Electricall and Computer Engineering ECE 35 Midterm Exam Winter 2010 Name (Last. First) Student ID Number SOIu-I—EQWS Signature This is a closed book exam, but you are allowed a single 8.5” x 11” sheet of notes. NO ELECTRONICS ARE ALLOWED: NO CALCULATORS, CELLPHONES, OR COMPUTERS You must show your work to receive credit on any problem. Write clearly: work which is not legible will not count towards your grade. Numeric answers MUST HAVE UNITS to be correct (Le, 30, 2A, 4mV) Always good exam policy: (1) READ THROUGH THE ENTIRE EXAM BEFORE BEGINNING (2) WORK ON THE SIMPLER PROBLEMS FIRST (3) TRY TO ANSWER ALL PROBLEMS Problem 1 ('5 pts): , w— ” "'" ‘- \ Sowruoi‘ (Pu cloalzs bH'tj-col miskr) l old-7 mn5ma‘7ic Pine: 40 UK a ggpgrxoatc’ 9;'|C¢ ow" hm: UM supplies are: Councc-‘f'C-l +0 awe-44 _ 1‘ k_ ; "1 A) For the circuit above. deﬁne a supernode and indicate it on the diagram. labelling the voltage at each terminal. B) Write an equation including only the variable Vx (relative to ground). 2. \ix = a: (V. 2U: *- V3) C} Solve for Vx in terms of the parameters shown in the circuit diagram. Vx = .1; (VI —2VZ +V3) Problem 2 (35 pts): + *- _').<., Switch A (dosed) 1 0 Switch 3 (open) 30V 40V Switch C I (ciosed) 1Q 40 In the complex circuit above, we are onl concerned with the volta e and current throu h the 10 (2 load resistor, at top. 30 A} Use resistor and source combination to reduce the circuit to the simplest form that retains the required voltage and current values (hint: it has 3 resistors and one voltage supply). Draw this circuit below. The. Ema cones-‘4- ﬁrth-H115 Luau-r. no impact- 54%.. vet-11.54 cm 44“ ion [gnarl since. on: is 193’4'9; ‘1 Siﬂeic— COHMLHOM 5°bC‘rC°:+ 4H4 it; cat-her is" Shari-c) 09+ 5;- '(‘L-g KVL. Pa-H.’ 5':- +64 CirLUH' (oi-«Ed» l! waded 35: m CnmLFm nﬁsbn 3' SD‘JV‘LCS :2; + 3"“ ”‘*°" ‘3 ﬂ 52:2. B) For the switches as shown above, calculate the voltage and current V). developed across the 100 load resistor. Vx= “\$3.5mI {T :: w1DV/(ID//i°+s>ﬂ- :1: #134 // Ix=‘_?z‘t\__ U014”: 4:944“ .- \i, = new. "i: 535‘»: Curr-cod- oliu'aoLev: i‘: iT/z : _%A C) Recalculate these values assuming that switch A is opened, and switch B is closed: Vx(=—Ou_._ Lﬁq‘. suit-4‘ A is OPCH. Mo Quinta-i Cam ﬁlth-5 lx‘=J__ Wmojh +£- Lead hiiS‘i-Or. Problem 3 (20 pts): A) Forthe circuit above, ﬁnd i1c KQL é3 Male. cg. ix=__ tA iii—7. =ix =2: [Ii-:1} -7_ KVL amend SUP-arm“. cuclﬁs'm, Ha; 2A Curr¢k+ Scorn: 2{,_ + 25K + 2(1.‘x 4-2133) +2(i2-(~2i,)) = o z (ix—z)+2ix v 2(i,+21‘x)+ 2(1‘x—2 +21‘A =o Zix _ 4 +21:" + zi‘wl‘gh‘x-‘HVC, =0 “nix-=8 . 8__l__ Ix'ln 2A B) Find the power provided by the dependent source. Pds=__L—__ We “6.154 val-Eu): alarms 'Hu. dQFcHOLeaol sum-J7 Val” I Vab=ﬂ{z ix +25)“: ' Zix “21.9”! 1 LI-Llix = 2" PA H N x.- 4 § 6“ 5 Problem 4 ([ 5'93): Find the Norton equivalent to the circuit below. =9 R RT = '5 K V0 =—v5 2+32—VS/2 V 1: ELE— _%_ V5 N‘ r— E“. _"_R_ Problem 5 (lifts): For the circuit at right, ﬁnd A) What value of load resistance, relative to R, maximizes the power dissipated in the load: q G: n RLOAD 2 —.i_ 30 RLOAD 3V B) What is that (maximum) power? 0 o 9 b -—- w PMAX = S FMJ Norhm egownlcwf: ﬁﬁr‘r b7 «Frans-Formiuj 4Q Carma-F surf/.25. . e =) lash-2 .': 12%;?W Problem 6 (20 pts): Find the Thevinin equivalent for the circuit below. N H a N——-3 R RT Vs o R <3 VT [0 b 2‘5. VT: 1: ﬂ RT: 1" EaSEe5+ ‘I'o L'mol RT 'From VDLE LC U KIiLCcP Noah a __ il __ 2i. + i. :0 :5 i = VOL I R ‘ 3R 0"" “5"ch _{ a " a => Vs"Vu=. V“- V -V —L\; :3: \J - V V :1 {a = ‘3? 5 0L"? Dc. 5 ﬂ 0;, ‘3"- Skori' make; 4a HALL, 4x; 42.1“! ISL ‘. _ \I -o [email protected] Sacha: *1|-Zi‘-"r1m:o :3 1&2372‘ : '5 22‘ =% 3U '11» n s ‘g R vac- T K T 15,; E33. L} '2 =21“:- ...
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• Winter '10
• JosephFord
• Circuit diagram, Electrical network, Norton's theorem, A Closed Book, load resistor, Califomr‘a San Diego

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ECE35 WIN10 Midterm Solutions - Lari-9r n It(mid-Lav...

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