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Unformatted text preview: \* Lari9r; n It; (midLav...) University of Califomr‘a San Diego
Department of Electricall and Computer Engineering ECE 35 Midterm Exam
Winter 2010 Name (Last. First) Student ID Number SOIuI—EQWS Signature This is a closed book exam, but you are allowed a single 8.5” x 11” sheet of notes. NO ELECTRONICS ARE ALLOWED: NO CALCULATORS, CELLPHONES, OR COMPUTERS You must show your work to receive credit on any problem.
Write clearly: work which is not legible will not count towards your grade. Numeric answers MUST HAVE UNITS to be correct (Le, 30, 2A, 4mV) Always good exam policy:
(1) READ THROUGH THE ENTIRE EXAM BEFORE BEGINNING (2) WORK ON THE SIMPLER PROBLEMS FIRST (3) TRY TO ANSWER ALL PROBLEMS Problem 1 ('5 pts): , w— ” "'" ‘ \ Sowruoi‘ (Pu cloalzs bH'tjcol miskr) l old7 mn5ma‘7ic Pine: 40 UK
a ggpgrxoatc’ 9;'C¢ ow" hm:
UM supplies are: Councc‘f'Cl
+0 awe44 _ 1‘ k_ ; "1 A) For the circuit above. deﬁne a supernode and indicate it on the diagram. labelling the voltage at each terminal. B) Write an equation including only the variable Vx (relative to ground). 2.
\ix = a: (V. 2U: * V3)
C} Solve for Vx in terms of the parameters shown in the circuit diagram. Vx = .1; (VI —2VZ +V3) Problem 2 (35 pts): + * _').<., Switch A
(dosed) 1 0
Switch 3 (open) 30V 40V Switch C I (ciosed) 1Q 40 In the complex circuit above, we are onl concerned with the volta e and current throu h the 10 (2 load resistor, at top. 30 A} Use resistor and source combination to reduce the circuit to the simplest form that retains the required voltage and
current values (hint: it has 3 resistors and one voltage supply). Draw this circuit below. The. Ema cones‘4 ﬁrthH115 Luaur. no impact 54%.. vet11.54 cm 44“ ion [gnarl since. on: is 193’4'9; ‘1 Siﬂeic— COHMLHOM 5°bC‘rC°:+ 4H4 it; cather is"
Sharic) 09+ 5; '(‘Lg KVL. PaH.’ 5': +64 CirLUH' (oi«Ed» l! waded 35: m CnmLFm nﬁsbn 3' SD‘JV‘LCS
:2; +
3"“ ”‘*°" ‘3 ﬂ 52:2. B) For the switches as shown above, calculate the voltage and current V). developed across the 100 load resistor. Vx= “$3.5mI {T :: w1DV/(ID//i°+s>ﬂ :1: #134
//
Ix=‘_?z‘t\__ U014”: 4:944“ . \i, = new. "i: 535‘»:
Currcod oliu'aoLev: i‘: iT/z : _%A C) Recalculate these values assuming that switch A is opened, and switch B is closed: Vx(=—Ou_._ Lﬁq‘. suit4‘ A is OPCH. Mo Quintai Cam ﬁlth5 lx‘=J__ Wmojh +£ Lead hiiS‘iOr. Problem 3 (20 pts): A) Forthe circuit above, ﬁnd i1c KQL é3 Male. cg.
ix=__ tA iii—7. =ix =2: [Ii:1} 7_
KVL amend SUParm“. cuclﬁs'm, Ha; 2A Curr¢k+ Scorn:
2{,_ + 25K + 2(1.‘x 42133) +2(i2(~2i,)) = o
z (ix—z)+2ix v 2(i,+21‘x)+ 2(1‘x—2 +21‘A =o
Zix _ 4 +21:" + zi‘wl‘gh‘x‘HVC, =0 “nix=8 . 8__l__
Ix'ln 2A B) Find the power provided by the dependent source. Pds=__L—__
We “6.154 valEu): alarms 'Hu. dQFcHOLeaol sumJ7 Val” I Vab=ﬂ{z ix +25)“: ' Zix “21.9”! 1 LILlix = 2" PA H
N
x.
4
§
6“ 5 Problem 4 ([ 5'93): Find the Norton equivalent to the circuit below. =9 R
RT = '5
K
V0 =—v5 2+32—VS/2
V
1: ELE— _%_ V5
N‘ r— E“. _"_R_ Problem 5 (lifts): For the circuit at right, ﬁnd A) What value of load resistance, relative to R, maximizes the power dissipated in the load: q
G: n
RLOAD 2 —.i_ 30
RLOAD
3V
B) What is that (maximum) power? 0 o 9 b — w
PMAX = S FMJ Norhm egownlcwf: ﬁﬁr‘r b7 «FransFormiuj 4Q CarmaF surf/.25. . e
=) lash2 .': 12%;?W Problem 6 (20 pts): Find the Thevinin equivalent for the circuit below. N H a N——3
R RT
Vs o R <3 VT
[0 b
2‘5.
VT: 1:
ﬂ
RT: 1"
EaSEe5+ ‘I'o L'mol RT 'From VDLE LC
U
KIiLCcP Noah a __ il __ 2i. + i. :0 :5 i = VOL
I R ‘ 3R
0"" “5"ch _{
a " a
=> Vs"Vu=. V“ V V —L\; :3: \J  V V :1
{a = ‘3? 5 0L"? Dc. 5 ﬂ 0;, ‘3"
Skori' make; 4a HALL, 4x; 42.1“! ISL ‘.
_ \I o
KQL@ Sacha: *1Zi‘"r1m:o :3 1&2372‘ : '5 22‘ =%
3U
'11» n s
‘g R vac T K
T 15,; E33. L}
'2 =21“: ...
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This note was uploaded on 02/16/2010 for the course ECE ECE 35 taught by Professor Josephford during the Winter '10 term at UCSD.
 Winter '10
 JosephFord

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