Unformatted text preview: equivalent resistance R eq = (4 Ω //4 Ω )//2 Ω = 2 Ω //2 Ω = 1 Ω , and V measured = 3 mA * 1 Ω = 3 mV. (2) The two 4 Ω resistors are equivalent to one 2 Ω resistor, and so by current division, half of the 3mA current flows through the 2 Ω resistor, from node A to node B, so I 20 = -1.5 mA (3) An ideal current meter connected to the current source shorts all current through itself, so no current flows through the resistors, and P 20 = 0 W 4 Ω 2 Ω 4 Ω i 20 =? 3mA Voltmeter +-A B...
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- Winter '10
- Volt, Resistor, Electrical resistance, Electrical impedance, Series and parallel circuits, ideal current meter