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Unformatted text preview: P2.25 (a) (b) Using the quadratic formula When v = 0.8 V then . When v = 1.0 V then . (c) Using the quadratic formula So there is no real solution to the equation. P2.45 P2.52 (a) (b) P2.61 (a) (b) The voltage, 12 V, and the current, 0.5 A, of the voltage source obey the passive convention so the power P = 12 (0.5) = 6 W is the power received by the source. The voltage source delivers 6 W. P2.65 a.) b.) Element Power supplied voltage source current source resistor total 0 P2.77 i d and v d adhere to the passive convention so is the power received by the dependent source. P2.93 (a) v = 12 V (b) (c) v = 0 V (d) (the box symbol was supposed to be ~, ‘approximately’) DP22 1.) 2.) Therefore 20 < R < 3.75 Ω . These conditions cannot be satisfied simultaneously....
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This note was uploaded on 02/16/2010 for the course ECE ece 45 taught by Professor Massimofranceschetti during the Winter '07 term at UCSD.
 Winter '07
 MassimoFranceschetti

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