HW2solutionsWIN10

# HW2solutionsWIN10 - ECE35 Win10 Homework 2 Solutions...

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ECE35 Win’10 Homework 2 Solutions Assignment: Finish reading chapter 3, and do at least the following problems: Problems: 3.2-8, 3.2-9, 3.2-10, 3.3-4, 3.3-7, 3.3-8, 3.4-4, 3.4-9, 3.4-14, 3.5-1, 3.6-1, 3.6-8, 3.6-15, 3.6-28, Design Problem 3-3 P3.2-8 P3.2-9 P3.2-10 KCL at node b : KCL at node a :

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P3.3-4 P3.3-7 All of the elements are connected in series. Replace the series voltage sources with a single equivalent voltage having voltage 12 + 12 – 18 = 6 V. Replace the series 15 Ω , 5 Ω and 20 Ω resistors by a single equivalent resistance of 15 + 5 + 20 = 40 Ω . By voltage division P3.3-8 Use voltage division to get Then The power supplied by the dependent source is given by
P3.4-4 P3.4-9 Each of the resistors is connected between nodes a and b . The resistors are connected in parallel and the circuit can be redrawn like this: Then So P3.4-14 Using KCL Using current division P3.5-1 The voltage sources are connected in series and can be replaced by a single equivalent voltage source. Similarly, the parallel current sources can

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HW2solutionsWIN10 - ECE35 Win10 Homework 2 Solutions...

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