thermo_ism_ch07

# thermo_ism_ch07 - Chapter 7: The Properties of Real Gases...

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Chapter 7: The Properties of Real Gases P7.1) –1 –2 –1 –1 –1 –2 –1 –1 2 –2 2 –1 –1 0.165 L 39.95 g 0.1883 Lmol 35.0 g mol 8.314 10 L bar K mol 390 K = 172 bar 0.1883 Lmol 8.314 10 L bar K mol 390 K 1.355L bar mol 0.1883 Lmol 0.0320 Lmol 0.18 m ideal gas m vdW m m V RT P V RT a P V b V = × = × × × = = × × = - = - - - ( 29 ( 29 ( 29 2 –1 –2 –1 –1 –1 –1 1 2 –2 2 –1 –1 –1 83 Lmol 169 bar 1 8.314 10 Lbar K mol 390 K 0.1883 Lmol 0.02219 Lmol 16.86 L bar mol K 1 0.1883 Lmol 0.1883Lmol + 0.02219 Lmol 390 K 174 bar RK m m m RK RT a P V b V V b T P = = - - + × × = - - = Because P vdW < P ideal gas , the attractive part of the interaction appears to dominate using the van der Waals equation of state. However, because P RK > P ideal gas , the repulsive part of the interaction appears to dominate using the Redlich-Kwong equation of state. This is a case where a more accurate equation of state is needed to answer the question. P7.2 ) ( 29 ( 29 –2 –1 –1 –2 –2 –1 –1 2 –2 2 2 –1 –1 8.314 10 Lbar K mol 375 K = 8.10 10 L 385 bar 8.314 10 L bar K mol 370 K 1.382 L bar mol 0.0319 Lmol The three solutions to this equation are 0.0131 0.0339 Lmol m vdW m m m m m RT V P RT a P V b V V V V i × × = = × × × = - = - - - = ± –1 –1 –1 –1 –1 –1 –1 and 0.0867 Lmol Only the real solution is of significance. 32.0 g mol = 395 g L 0.0810 Lmol 32.0 gmol = 369 gL 0.0867 Lmol m idealgas m vdW m V M V M V ρ = = = = = Because the van der Waals density is less than the ideal gas density, the repulsive part of the potential dominates. 7-1

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Chapter 7/The Properties of Real Gases P7.3) For the ideal gas, ( 29 ( 29 –1 –2 –1 –1 –2 –1 –1 –1 1 2 –2 2 –1 1 400 bar = 9.62 molL 8.314 10 Lbar K mol 500 K 1 8.314 10 Lbar K mol 500 K 400 bar = 0.02208 Lmol 17.40 L bar mol K 1 + 0.02208 Lmol 500 K The m RK m m m m m m P V RT RT a P V b V V b T V V V = = × × = - - + × × - - ( 29 –1 –1 –1 –1 three solutions to this equation are 0.00529 0.0186 Lmol and 0.1145 Lmol Only the real solution is of significance. 1 1 = 8.73 molL 0.1145 Lmol m m m V i V V = - ± = = The ideal gas density is greater than that calculated with the Redlich-Kwong equation of state and the experimental result showing that the repulsive part of the potential dominates. The Redlich-Kwong result is in error by +10%. P7.4) ( 29 3 3 3 6 –2 2 –2 –1 –1 3 for a van der Waals gas. In solving this problem, keep in mind that 1 dm 1 L = 10 m . 0.2452 dm bar mol
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## This note was uploaded on 02/16/2010 for the course CHEM 550 taught by Professor Abra during the Fall '09 term at Penn State.

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thermo_ism_ch07 - Chapter 7: The Properties of Real Gases...

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