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Unformatted text preview: Abd Elhai, Mohamed – Homework 12 – Due: May 10 2008, 9:00 pm – Inst: Dr Kevin Dean 1 This printout should have 18 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. The due time is Central time. This is ONLINE HOMEWORK No. 12 It is due by 06:00 AM Abu Dhabi Time on Thursday 8 May (9:00 PM Wed. 7 May, Texas time). 001 (part 1 of 4) 5 points A traveling wave propagates according to the expression y = (3 . 95 cm) sin[(1 . 45 cm 1 ) x (2 . 86 s 1 ) t ] , where x is in centimeters, and t is in seconds. Determine the amplitude of the wave. Correct answer: 3 . 95 cm. Explanation: Given a wave y = A sin( k x ω t ), where the amplitude of the wave is A . In our case, A = 3 . 95 cm . 002 (part 2 of 4) 5 points Determine the wavelength of the wave. Correct answer: 4 . 33323 cm. Explanation: The angular wave number of the wave is k = 1 . 45 cm 1 and its relation to the wavelength λ is λ = 2 π k = 4 . 33323 cm . 003 (part 3 of 4) 4 points Determine the frequency of the wave. Correct answer: 0 . 455183 Hz. Explanation: The angular frequency of the wave is ω = 2 . 86 s 1 and the frequency is f = ω 2 π = 0 . 455183 Hz . 004 (part 4 of 4) 4 points Determine the period of the wave. Correct answer: 2 . 19692 s. Explanation: The period of the wave is T = 1 f = 2 . 19692 s . keywords: 005 (part 1 of 3) 5 points A taut string of length 7 . 7 m and mass 32 g is under a tension of 43 N. Transverse sinusoidal waves with amplitude of 5 . 1 cm and a wavelength of 2 . 1 m are traveling along the string. What is the speed of the wave? Correct answer: 101 . 72 m / s. Explanation: Let : l = 7 . 7 m , m = 32 g , and F = 43 N . The string has linear mass density μ = m l = 32 g 7 . 7 m 1 kg 1000 g = 0 . 00415584 kg / m , so the wave speed v w = s F μ = 101 . 72 m / s ....
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 Spring '09
 NAJAFZADEH
 mechanics, Work, Correct Answer, Dr Kevin Dean, Abd Elhai

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