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Unformatted text preview: Suppose approximately 80% of OSU students are in favor of the smoking ban. Two OSU students are selected at random. 6. What is the probability that both of them support the smoking ban? P(YY) = (.8)(.8) ANS .64 7. What is the probability that both of them oppose the smoking ban? P(NN) = (.2)(.2) ANS .04 8. What is the probability that at least one of them supports the smoking ban? P(YN) + P(NY) = (.8)(.2) + (.2)(.8) ANS .32 1 Use the following information for problems 9-10: Let X be the amount of cash a customer withdraws from their account at the bank. Let X have a Normal distribution with mean $100 and standard deviation $25. 9. Find the 75th percentile for X. ANS $116.75 10. Find the probability that one customer chosen at random withdraws less than $60. M x = $100 σ x = $25 ANS .0548 2...
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This note was uploaded on 02/16/2010 for the course STAT 133 taught by Professor Rumseyjohnson during the Fall '07 term at Ohio State.
- Fall '07