AssignmentITEC1000_1AnswersWinter2010

AssignmentITEC1000_1AnswersWinter2010 - AP/ITEC1000...

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AP/ITEC1000 Sections M and N "Introduction to Information Technologies" Winter 2010 Assignment #1 Answers and Solutions 1.a 4703 10 = 1001001011111 2 because 4703 / 2 = 2351 remainder 1 2351 / 2 = 1175 remainder 1 1175 / 2 = 587 remainder 1 587 / 2 = 293 remainder 1 293 / 2 = 146 remainder 1 146 / 2 = 73 remainder 0 73 / 2 = 36 remainder 1 36 / 2 = 18 remainder 0 18 / 2 = 9 remainder 0 9 / 2 = 4 remainder 1 4 / 2 = 2 remainder 0 2 / 2 = 1 remainder 0 1 / 2 = 0 remainder 1 1.b 537.5 10 = 1000011001.1 2 because 537 / 2 = 268 remainder 1 And 0.5 268 / 2 = 134 remainder 0 x 2 134 / 2 = 67 remainder 0 1.0 67 / 2 = 33 remainder 1 33 / 2 = 16 remainder 1 16 / 2 = 8 remainder 0 8 / 2 = 4 remainder 0 4 / 2 = 2 remainder 0 2 / 2 = 1 remainder 0 1 / 2 = 0 remainder 1 1.c 0.63827 10 = 0.10100.. 2 because
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0.63827 x 2 1.27654 x 2 0.55308 x 2 1.10616 x 2 0.21232 x 2 0.42464 2.a 1100110 2 = 2 6 + 2 5 + 2 2 + 2 1 = 64 + 32 + 4 + 2 = 102 10 2.b 10100.110 2 = 20.75 10 because 10100 2 = 2 4 + 2 2 = 16 + 4 = 20 10 And 0.110 2 = 2 -1 + 2 -2 = 0.5 + 0.25 = 0.75 10 2.c 0.11101 2 = = 2 -1 + 2 -2 + 2 -3 + 2 -5 = 0.5 + 0.25 + 0.125 + 0.03125 = 0.90625 10 3.a E7F5 16 = 1110011111110101 2 because E 16 = 1110 2 7 16 = 0111 2 F 16 = 1111 2 5 16 = 0101 3.b 64.C3 16 = 1100100.11000011 2 because 6 16 = 0110 2 4 16 = 0100 2 C 16 = 1100 2 3 16 = 0011 3.c 0.F12 16 = 0.11110001001 2 because F 16 = 1111 2 1 16 = 0001 2 2 16 = 0010 2 4.a 10101101101 2 = 56D 16 because 1101 2 = D 16 0110 2 = 6 16 0101 2 = 5 16
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4.b 11100.01011 2 = 1C.58 16 because 1100 2 = C 16 0001 2 = 1
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