Unformatted text preview: CHAPTER 3 Section 31 31. 32. 33. 34. 35. The range of X is {0,1,2,...,1000} The range of X is {0,12,...,50} , The range of X is {0,12,...,99999} , The range of X is {0,12,3,4,5} , The range of X is 1,2,...,491 . Because 490 parts are conforming, a nonconforming part must be selected in 491 selections. The range of X is {0,12,...,100} . Although the range actually obtained from lots typically might not , exceed 10%. { } 36. 37. The range of X is conveniently modeled as all nonnegative integers. That is, the range of X is , {0,12,...} The range of X is conveniently modeled as all nonnegative integers. That is, the range of X is , {0,12,...} The range of X is 38. 39. 310. {0,1,2,...,15} The possible totals for two orders are 1/8 + 1/8 = 1/4, 1/8 + 1/4 = 3/8, 1/8 + 3/8 = 1/2, 1/4 + 1/4 = 1/2, 1/4 + 3/8 = 5/8, 3/8 + 3/8 = 6/8. ⎧1 3 1 5 6⎫ Therefore the range of X is ⎨ , , , , ⎬ ⎩4 8 2 8 8 ⎭ The range of X is 311. {0,1,2, … ,10000} 312.The range of X is {100, 101, …, 150} 313.The range of X is {0,1,2,…, 40000) Section 32 314. f X (0) = P ( X = 0) = 1 / 6 + 1 / 6 = 1 / 3 f X (1.5) = P ( X = 1.5) = 1 / 3 f X (2) = 1 / 6 f X (3) = 1 / 6
a) P(X = 1.5) = 1/3 b) P(0.5< X < 2.7) = P(X = 1.5) +P(X = 2) = 1/3 + 1/6 = 1/2 c) P(X > 3) = 0 d) P ( 0 ≤ X < 2) = P ( X = 0) + P ( X = 1.5) = 1/ 3 + 1/ 3 = e) P(X = 0 or X = 2) = 1/3 + 1/6 = 1/2 2/3 315. All probabilities are greater than or equal to zero and sum to one. 31 ...
View
Full Document
 Spring '10
 Feng
 Addition, Negative and nonnegative numbers

Click to edit the document details