Chapter 17 Some solutions given tostudents Questions 1,2 3 and 10

Chapter 17 Some solutions given tostudents Questions 1,2 3 and 10

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Chapter 17 Electric Potential Solutions to Problems 1. The work done by the electric field can be found from Eq. 17-2b. ( 29 ( 29 6 4 ba ba ba ba 7.7 10 C 55 V 4.2 10 J W V W qV q - - = - = - = - - × + = × 2. The work done by the electric field can be found from Eq. 17-2b. ( 29 ( 29 ( 29 ( 29 19 2 17 ba ba ba ba 2 1.60 10 C 1.80 10 V 2.88 10 J 1 180 V 1.80 10 eV W V W qV q e - - = - = - = - × - × = × = - - = × 3. The kinetic energy gained is equal to the work done on the electron by the electric field. The potential difference must be positive for the electron to gain potential energy. Use Eq. 17-2b. ( 29 ( 29 ( 29 ( 29 19 4 15 ba ba ba ba 4 4 1.60 10 C 2.3 10 V 3.7 10
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Unformatted text preview: J 1 2.3 10 V 2.3 10 eV W V W qV q e--= - = -= - - = = - - = 10. By the work energy theorem, the total work done, by the external force and the electric field together, is the change in kinetic energy. The work done by the electric field is given by Eq. 17-2b. ( 29 ( 29 external electric final initial external b a final 4 4 2 external final b a 6 KE KE KE KE 15.0 10 J 4.82 10 J 1.20 10 V 8.50 10 C W W W q V V W V V q---+ =---= ---= = = --...
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This note was uploaded on 02/18/2010 for the course WER 865 taught by Professor Io during the Spring '10 term at PA Culinary.

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