HW 31 - terry (ect328) – homework 31 – Turner –...

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Unformatted text preview: terry (ect328) – homework 31 – Turner – (59130) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points The current in a light bulb is plotted as a function of angular velocity ω as shown below. ω I lightbulb Select the circuit which gives rise to the above plot. 1. R E C L 2. R E C L cor- rect 3. R E C L 4. R E C L 5. None of these Explanation: X C = 1 ω C and X L = ω L. Analyze each circuit: R E C L Z RC = radicalBig R 2 + X 2 C = radicalBigg R 2 + 1 ( ω C ) 2 I R = E radicalbigg R 2 + 1 ( ω C ) 2 ω I lightbulb ω ω = 1 RC ====================== R E C L Z RL = radicalBig R 2 + X 2 L = radicalBig R 2 + ( ω L ) 2 I R = E radicalbig R 2 + ( ω L ) 2 ω I lightbulb ω ω = R L ====================== R E C L terry (ect328) – homework 31 – Turner – (59130) 2 Z = R + 1 radicalBigg parenleftbigg 1 X C- 1 X L parenrightbigg 2 = R + 1 radicalBigg parenleftbigg ω C- 1 ω L parenrightbigg 2 I R = E R + 1 radicalBigg parenleftbigg ω C- 1 ω L parenrightbigg 2 ω I lightbulb ω ω = 1 √ LC ====================== R E C L Z = radicalBig R 2 + ( X L- X C ) 2 = radicalBigg R 2 + parenleftbigg ω L- 1 ω C parenrightbigg 2 I R = E radicalBigg R 2 + parenleftbigg ω L- 1 ω C parenrightbigg 2 ω I lightbulb ω ω = 1 √ LC 002 10.0 points A circuit containing a resistor and an in- ductor is shown below. R L b a Select the plot commensurate with the above circuit in which the impedance from a to b is plotted as a function of angular ve- locity ω ....
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This note was uploaded on 02/17/2010 for the course PHY 59130 taught by Professor Turner during the Fall '09 term at University of Texas.

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HW 31 - terry (ect328) – homework 31 – Turner –...

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