Discussion 1 key only Spring 2010

Discussion 1 key only Spring 2010 - GENETICS (BIO 325)...

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GENETICS (BIO 325) Spring 2010 Discussion 1 key ____________________________________________________________ 1. (b) and (e) 2. Cross the yellow plant with a normal plant. Self the resulting F 1 and look for a consistent, predictable segregation pattern. For example, the presence of a 3 green: 1 yellow segregation ratio would suggest that the yellow phenotype was caused by a recessive mutation. 3. (a) testcross (b) You will observe different segregation in the testcross progeny, depending on the genotype of the red petunia. If the red petunia is R/R, then all testcross progeny will be red; if the red petunia is R/r, then ½ of the testcross progeny will be red (R/r) and ½ will be white (r/r). 4. (a) 36 (b) 36 5. (e) 6. The F 2 genotypic ratio is 1 B/B; 2 B/b; 1 b/b. Considering only the black F 2 , we expect 1 B/B : 2 B/b or two out of every three black guinea pigs to be heterozygous; the fraction is 2/3. 7.
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This note was uploaded on 02/17/2010 for the course BIO Genetics taught by Professor Saxena during the Spring '08 term at University of Texas at Austin.

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Discussion 1 key only Spring 2010 - GENETICS (BIO 325)...

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