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assignment 24 solutions

# assignment 24 solutions - Problem 2.69 2.69 A fabric used...

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Unformatted text preview: Problem 2.69 2.69 A fabric used in air-inﬂated structures is subjected to a biaxial loading that results in normal stresses ox = 120 MPa and a, = 160 MPa. Knowing that the properties of the fabric can be approximated as E = 87 GPa and v = 0.34, determine the change in length of (a) side AB, (1;) side BC, (c) diagonal AC. 6x = noilo‘ Pa, C5,: 0, 6; = 1402(0‘ ’94:. Ex: E—.'(€x‘ v63 'vG-z) ‘: 87in)? l: mom-"6 ‘ (0-34chwlo‘ﬂ = 759.02 Xlo“ 52 = fﬂvs’, — 116:, + 6;) = WE-Casﬁﬁzouo‘) + lsowo‘] : 1,370: We" (a) 532(14—8 is, = (100m)(75‘r.02xlo"‘) ? 0.0754 mm 4 (L) \$k=(e_c)£2 = (.75MM)(.[-37OIX lo“ 3 - 0.1023 Mn 4 A “L 3 Led:le .Siale: «Pv‘cgh‘ frl‘aane ABC as aJ L) me! C. c b C." = Out-t £1 Okla-3n AﬁF‘Feu/‘en‘l‘t‘a’s Lx/ CaijIUS, 2C alc; = 20.le + 25 a“: dc. = % ale. + -E- AL, Bu+J Q: 100 mm.) b: IOOm-nJ err/rooﬁng ‘) = 115‘ m». dd: gmg, = 0-0759 ham = \$3; 7’ C 0.1370 Va». _ _ loo 75 (:3 SM — dc - 5'25, (0.07\$&)+ '25 (0.1028) = arm-a mm d Problem 2.73 2.73 In many situations it is known that the normal stress in a given direction is zero, for example a, = 0 in the case of the thin plate shown. For this case, which is known as plane stress, show that if the strains 6, and s, have been determined experimentally, we'can express 6,, a, and a, as fOIIOWS: V €+V€ €+V£ x y _ y X _ a=E a-_E €__ x 1_V2 y l_V2 Z 1_ yam) 8,: ﬁ<srv63> m adhg—véjﬂsg) (2) Mup+5ppfinj (23 by v and” «Ag/inf]. +c (ll _ 7. EX+VEJ=IE7J61 or 6,: E (2+u513 <5 Muﬁ+;pj’7;n3 m LY 7/ ma Mum +om ...
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assignment 24 solutions - Problem 2.69 2.69 A fabric used...

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