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Unformatted text preview: x ê L L „ x = (4) b n = 1 ÅÅÅÅ L ‡ L Sin H n p x ê L L „ x = -1 ÅÅÅÅÅÅÅ n p Cos H n p x ê L L x = L + 1 ÅÅÅÅÅÅÅ n p Cos H n p x ê L L x = = J 1-Cos H n p L ÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅÅ ÅÅÅÅÅÅÅÅÅÅÅÅÅ n p N Thus (5) b n = 2 ÅÅÅÅÅÅÅÅ n p for n odd b n = for n even 2 Problem3.2.2f.nb...
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This note was uploaded on 02/18/2010 for the course ENGINEEING 32145 taught by Professor Stroeve during the Fall '09 term at Universidad de Carabobo.
- Fall '09