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ü Problem 1.4.1(f) The differential equation and BCs at steady state are given by (1) d 2 u ÅÅÅÅÅÅÅÅ dx 2 + Q ÅÅÅÅÅ K o , u H 0 L = T , d u ÅÅÅÅÅÅ dx H L L = 0 where Q ê K 0 = x 2 . The general solution (after integrating twice) is (2) u H x L = - x 4 ÅÅÅÅÅ 12 + c 1 x + c 2 Applying the BCs gives (3) c 2
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This note was uploaded on 02/18/2010 for the course ENGINEEING 32145 taught by Professor Stroeve during the Fall '09 term at Universidad de Carabobo.
- Fall '09