eng 45 homework3_sol2 - "'Jl—IJI.IIIJ I u 3.30(3...

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Unformatted text preview: "'Jl—IJI.IIIJ I' u 3.30. (3) Sketch. in a cubic unit cell, [100] and [210] di- rections. (1:) Use a trigonometric calculation to de- termine the angle between these directions. (1:) Use Equation 3.3 to determine this angle 5“: Elia-m _ _ hf; ,, r- “4... a :4". 4-... (V1): 36.5. (a) 5-: art as 2+o+a WW7: teat-c (as 1?_-5_— -'-' 26.5. 3.35. A useful rule of thumb for the cubic system it than given [an] Citation in the normal In the (m) 9% Using this rule and Equation 3,}. Imam-Line which members of the (110} family of dixeefiens lie mum: the (111} plane. (Hints The dot product of two perpendicular vectors is zero.) 0:01. 4.4. filial hon-u! f. (w) __ M [M] m‘flJM-n 3m («f/”Ag" mag .- _ [Ta-J, [I Ta 1, £ rm]. Us 7]. [M], a.) £977] _ 3.44. The four—digit notation- system (Miller-Brant in— dices) inn-canted for planes in the hexagonal sync!!!- can also be used for deseribingcrystal directions. 'In a hexagqnal uni_t eeil sketch (8)1118 [0001] direction. and (b)'1h:[1120] direction. 3.78. The diffraction peaks Iabeled in Figure 3:39 corre- spond to the reflection rules for'an foe meta] (h. k. I unmixed. as shown in Table 3.4). What would be the (Mr!) indices for the three lowest diffraction anye peaks for a bee metal? me, we run" M'flé {4: 5.4%.. : ' kWh-[Inb- nun-J“ Sec-n4, M a... Chu‘Jhc, E’ml‘m 3.5% 3.6: .3151 9- fig-1f an} ‘5‘]! :97 W?“ (Lu): (It-o) (200) £425 1.44;): a 2 4‘ A‘JP-d': A 4' 6 3.79 Using the result of Problem 3.73. calculate the difiractinn angles (29) for the first three peaks in the difimctiun pu- tem of cal-Fe powder using Can-radiation (1 = 0.1542 . nm) For cat-Fe, flaw-4r}: or a: (4”?)52 = (4WJKMJJh. ; = 0.236 a... d = 0.336 to": 0-”‘un {n+0 2 J . 0.23611 - Gillian-1 . an gfi a .0. 143:... d 0.216.... _ c.2361... gull/1%)“ - 1’6 Indra... 0.154230” armada... - 0.29: “In 9m=mm - 2.3.4- «- res)”.- 44.2- eme'Hv-fij—jg-i : 32.5' r (30)“,- 65.33 I n a“ . -- 0.154: - .. '_ o 93.. ““253: 4“" " 3"»? ”5 ...
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