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Unformatted text preview: the same as in part A and so is the conversion; the composition of the reactor is the same everywhere and equal to that of the product stream (because it is a backmix reactor [and operated at steady state]). Therefore the rate is the same as in part A and can be calculated from the given information: r = ( C A0 C Aproduct )/( V / v ) [this is the design equation for the backmix reactor] So we calculate the rate r = (1.00 0.05)/(50/60) = 1.14 mol/(liter min) Now, use the given information to solve for V : 1.14 = 0.95/( V /3,500); V = 2,917 liter C. A steadystate backmix reactor with a volume of 10,000 L was used with the same feed and gave a conversion of 95%. What was the volumetric flow rate of the feed? Again, the rate is the same and we use the design equation to solve for v : r = 1.14 = 0.95/(10,000/ v ); v = 12,000 liter/min...
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 Fall '09
 Stroeve

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