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lec23

# lec23 - Test#2 Oct 22 2009 Thursday 6:30 7:30 PM FRNY G140...

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1 1 Test #2 Oct. 22, 2009, Thursday, 6:30 - 7:30 PM, FRNY G140 No calculator, no formula sheet, no cell phone. Tables 13.1 and 13.2 will be handed out with the test. Material covered: Chap. 14, 15, 16 and 17, and notes HW#4, #5, #6 and #7 A seating chart will be posted in 202 Help Room and on my office door (MSEE 262) by 10/22/09 noon. You have to sit in the assigned seat only. MC and WO questions. Turn in the scantron sheet and the test packet. Bring PU ID Class as usual, 10/19/09 (Mon.) and 10/21/09 (Wed.) HW #7 is due on 10/19/09, today No class, 10/23/09, Friday 2 Summary of Lecture #23 10/19/09 ϖ o , ϖ r , ϖ m , ϖ p , ϖ d , B ϖ , Q etc. Bandpass characteristic of series and parallel RLC circuits Pole-zero plots of circuits with an ideal capacitor and an ideal inductor each No finite zero and two complex poles Single zero at the origin and two complex poles Single zero off the origin and two complex poles Two finite zeros and two complex poles Circuits with real or practical inductors and capacitors 3 Undamped natural freq., tank freq., LC freq. : ϖ o Reactance (or susceptance) of L = reactance (or susceptance) of C Resonant frequency: ϖ r i in (t) and v in (t) are in time phase. ϖ r , if exists, is proportional to ϖ o . Im [Z in (j ϖ )] = 0 or Im[Y in (j ϖ )] = 0 at ϖ r Peak freq uency , ϖ m , (Fig. 16.1 of handout) Pole frequency . ϖ p , (Fig. 16.2 of handout) Damped oscillation freq . ϖ d , (Fig. 16.2 of handout) (Fig. 17.7 and Fig. 17.11 of textbook) L C L C i in (t) v in (t) + - LC 1 o = ϖ 4 Peak frequency : ϖ m Half power frequency: ϖ 1 and ϖ 2 Half power bandwidth : B ϖ = ϖ 2 - ϖ 1 Pass band: [ ϖ 1 , ϖ 2 ] Quality factor Q: High Q: Q > 10 Low Q: Q < 1 For high Q circuits, 2 B ~ 0 1 2 ϖ ± ϖ ϖ ϖ ϖ ϖ ϖ ϖ = B / ~ B / Q m 2 1 ϖ m ϖ 2 ϖ 1 5 Bandpass characteristic of parallel RLC circuits x x o 2 o r 1/ 2 2 2 1 1 Y(s) Cs R Ls 1 (1/ C)s Z(s) s 1 Y(s) s RC LC 1 Z(j ) 1 1 j( C ) R L Im[ Z(j ) ] 0 if 1/ LC 1 1 | Z(j ) | ( C ) R L - = + + = = + + ϖ = + ϖ - ϖ ϖ = ϖ = ϖ = ϖ = + ϖ -

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