tgs trk2 - dZ/dX = (Fao/(ra)*b*A) dT/dX =( (Hr)*Fao )-

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ra = 305E5*(((Fao*(1-X)*Pt/(Ft0-0.5*Fao*X))^0.38)*(exp (-28000/R/T)) ID = 1 inch b = ρ 50.0000 lb/ft3 Hr = Δ A = 0.7850 inch2 R = 0.0055 ft2 = π G = 400.0000 lbm/(h)(ft2) Pt = 2.1804 lbm/h D = BM gas = 29.0990 lbm/lbmol Tw = Ft0 (mol G) = 0.0749 lbmol/h mol udara = 0.0749 lbmol udara/ h (hw*dp)/Kf = 2. FB0 (mol O2) = 0.0157 lbmol O2/h Re = FI0 (mol N2) = 0.0591 lbmol N2/h Pr = FA0 (mol naphthalene)= 0.0001 lbmol naphthalene/h ITERASI KE-0 X X Δ T0,K Z, ft ra X0 0 0.1 613 0 0 0.05 0.1 613 0 0 0.05 0.1 613 0 0 X0 + X Δ 0.1 0.1 613 0 0 KE-1 X X Δ T0,K Z, ft ra X0 0.1 0.1 613 0.14 0 X0 + ( X/2) Δ 0.15 0.1 613 0.14 0 X0 + ( X/2) Δ 0.15 0.1 613 0.14 0 X0 + X Δ 0.2 0.1 613 0.14 0 KE-2 X X Δ T0,K Z, ft ra X0 0.2 0.1 613 0.28894419 0 X0 + ( X/2) Δ 0.25 0.1 613 0.28894419 0 X0 + ( X/2) Δ 0.25 0.1 613 0.28894419 0 X0 + X Δ 0.3 0.1 613 0.28894419 0 KE-3 X X Δ T0,K Z, ft ra X0 0.3 0.1 613 0.45281772 0 dZ/dX = (Fao/((ra)* b*A)) ρ dT/dX =(( ( Hr)*Fao )- (hw*(T-Tw)* *D*(dZ/dX)))/(Ft*Cp) Δ π X0 + ( X/2) Δ X0 + ( X/2) Δ
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X0 + ( X/2) Δ 0.35 0.1 613 0.45281772 0 X0 + ( X/2) Δ 0.35 0.1 613 0.45281772 0 X0 + X Δ 0.4 0.1 613 0.45281772 0 KE-4 X X Δ T0,K Z, ft ra X0 0.4 0.1 613 0.62544632 0 X0 + ( X/2) Δ 0.45 0.1 613 0.62544632 0 X0 + ( X/2) Δ 0.45 0.1 613 0.62544632 0 X0 + X Δ 0.5 0.1 613 0.62544632 0 KE-5 X X Δ T0,K Z, ft ra X0 0.5 0.1 613 0.80791344 0 X0 + ( X/2) Δ 0.55 0.1 613 0.80791344 0 X0 + ( X/2) Δ 0.55 0.1 613 0.80791344 0 X0 + X Δ 0.6 0.1 613 0.80791344 0 KE-6 X X Δ T0,K Z, ft ra X0 0.6 0.1 613 1.00278105 0 X0 + ( X/2) Δ 0.65 0.1 613 1.00278105 0 X0 + ( X/2) Δ 0.65 0.1 613 1.00278105 0 X0 + X Δ 0.7 0.1 613 1.00278105 0 KE-7 X X Δ T0,K Z, ft ra X0 0.7 0.1 613 1.21453803 0 X0 + ( X/2) Δ 0.75 0.1 613 1.21453803 0 X0 + ( X/2) Δ 0.75 0.1 613 1.21453803 0 X0 + X Δ 0.8 0.1 613 1.21453803 0 X Z T,C 0 0 340 0.1 0.14 335.86 0.2 0.28894419 334.77 0.3 0.45281772 334.63 0.4 0.62544632 334.78 0.5 0.80791344 335.03 0.6 1.00278105 335.35 0.7 1.21453803 335.73 0.8 1.45175464 336.21 334 336 338 340 342 UBUNGAN ANT
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0 0.2 330 332 334 0 0.2 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 BUNGAN ANTA 0 0.1 330 332 334 336 338 340 342 AFIK HUBUNG
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-7300 Btu/lb 1.99 cal/lbmol K 3.14 1 atm 0.08 ft 613 K 644 ft .58*((Re)^(1/3))*((Pr)^(1/3)) + 0.094 *((Re)^0.8)*((Pr)^0.4) ( *v*dp)/μ ρ dZ/dX k T,K T,C T,F dT/dX 1.2 0.12 T0 613 340 644 -70.79 1.4 0.14 T0+(L1/2) 609.46 336.46 637.63 -31.9 1.3 0.13 T0+(L2/2) 611.41 338.41 641.13 -54.51 1.53 0.15 T0+L3 607.55 334.55 634.19 -5.04 Z = Δ 0.14 T = Δ dZ/dX k T,K T,C T,F dT/dX 1.46 0.15 T0 608.86 335.86 636.54 -23.23 1.56 0.16 T0+(L1/2) 607.69 334.69 634.45 -5.75 1.51 0.15 T0+(L2/2) 608.57 335.57 636.02 -18.24 1.63 0.16345752 T0+L3 607.03176178 334.03 633.26 6 Z = Δ 0.15367119 T = Δ dZ/dX k T,K T,C T,F dT/dX 1.59 0.16 T0 607.77 334.77 634.58 -5.36 1.65 0.16 T0+(L1/2) 607.5 334.5 634.1 0.43 1.63 0.16 T0+(L2/2) 607.79 334.79 634.62 -4.06 1.7 0.17 T0+L3 607.36 334.36 633.85 4.55 Z = Δ 0.16 T = Δ dZ/dX k T,K T,C T,F dT/dX 1.68 0.17 T0 607.63 334.63 634.34 0.18 (Cp*μ)/Kf
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1.73 0.17 T0+(L1/2) 607.64 334.64 634.36
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This note was uploaded on 02/18/2010 for the course CHEMENG pap taught by Professor Sumardi during the Spring '10 term at Imperial College.

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tgs trk2 - dZ/dX = (Fao/(ra)*b*A) dT/dX =( (Hr)*Fao )-

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