Answer to 2006 CHE 141 Exam I

Answer to 2006 CHE 141 Exam I - 3:2, and the empirical...

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Answer to 2006 CHE 141 Exam I Multiple Choice Questions: Form 1 (Green) DADDEC Q7 If the collisions were inelastic, some energy would be lost over time, and the gas sample would spontaneously cool down, even if perfectly insulated. This violates conservation of energy and common sense. Q8 The compound is made of just C and O, so it's 52.96% C and 47.04% O. Assume a 100 g sample, which contains 52.96 g C = 4.41 moles C and 47.04 g O = 2.94 moles O. The ratio of 4.41/2.94 = 1.50, so the ratio is
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Unformatted text preview: 3:2, and the empirical formula is C3O2. Q9 n/V = P/RT = 1 atm/(0.0822)(300) = 0.0405 moles/L. Since there are 2.76 g/L, then 2.76 g = 0.0405 mole. Therefore, 1 mole weighs 68.1 g. The empirical formula from Q8 would be 68, so the molecular formula is the same as the empirical formula, C3O2. Q10 Boyle's law applies to a given sample of gas at a constant temperature. When the tires are being filled, though, the quantity of gas in the tire (n) is changing. So Boyle's law doesn't apply....
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This note was uploaded on 02/18/2010 for the course PSY 101 taught by Professor La during the Spring '08 term at SUNY Stony Brook.

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