# le11 - E E 2315 Lecture 11 Natural Responses of Series RLC...

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E E 2315 Lecture 11 Natural Responses f Series RLC of Series RLC Circuits

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1 Natural Response of Series RLC (1/5) R L C t = 0 + v c - i KVL for t 0: but Natural Response of Series RLC (2/5) R L C t = 0 + v c - i KVL for t 0: Differentiate: From experience with 1st order problems: Substitute into last KVL equation: Natural Response of Series RLC (3/5) Divide out then
2 Natural Response of Series RLC (4/5) Solve for a: Let and Then Natural Response of Series RLC (5/5) Three types of response: real and unequal (both negative) real and equal (negative) complex conjugate pair Overdamped Series RLC (1/6) 5 250 mH 62.5 mF + v c i t = 0 -

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3 Overdamped Series RLC (2/6) 5 250 mH 62.5 mF t = 0 + v c i - Overdamped Series RLC (3/6) Now use initial conditions to find k 1 and k 2 . then Overdamped Series RLC (4/6) 5 250 mH 62.5 mF + v c i t = 0 -
4 Overdamped Series RLC (5/6) 40 60 Capacitor Voltage 0 0.2 0.4 0.6 0.8 0 20 v c t () t Overdamped Series RLC (6/6) 0 Inductor Current 0 0.2 0.4 0.6 0.8 10 5 it Critically Damped Series RLC (1/6) 4 250 mH 62.5 mF + v c i t = 0 -

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## This note was uploaded on 02/20/2010 for the course EE 2315 taught by Professor Staff during the Fall '08 term at UT Arlington.

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le11 - E E 2315 Lecture 11 Natural Responses of Series RLC...

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