Le03 - EE2315 Lecture03 Simple Applications R l A When conductor has uniform cross-section cu 1.67 106 cm al 2.70 106 cm Area A len Metallic

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1 E E 2315 Lecture 03 Simple Resistive Circuits and Applications Calculating Resistance When conductor has uniform cross-section R A l 6 1.67 10 cu cm  6 2.70 10 al cm Area, A len Temperature Coefficient of Resistance Metallic conductors have a linear increase of resistance with increased temperature. T o is the reference temperature (usually 20 o C) and R o is the  () 1 oo R TR T T    resistance at the reference temperature. is the temperature coefficient of resistance for the material. At 20 o C, some values for are: Material Alpha @ 20 o C Aluminum 0.004308 Copper 0.004041
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2 Resistors in Series V s R 1 R 2 + V 1 - I s I 1 I 2 + V 2 - + V s - V s R eq I s By KCL: I s = I 1 = I 2 By Ohm’s Law: V 1 = R 1 ·I 1 and V 2 = R 2 ·I 2 Combine: V s = R 1 I 1 + R 2 I 2 = (R 1 + R 2 ) I s = R eq I s In General: R eq = R 1 + R 2 +···+ R n Resistors in Parallel (1/2) I s R 1 R 2 + V 1 - I 1 I 2 + V 2 - + V s - + V s - I s R eq By KVL: V s = V 1 = V 2 By KCL: I s = I 1 + I 2 By Ohm’s Law: and Combine: 1 1 1 V I R 2 2 2 V I R Resistors in Parallel (2/2) For two resistors: For many resistors: In terms of conductance: 12 11 1 1 eq n R RR R  eq n GGG G 
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3 Voltage Divider Circuit V s R 1 R 2 + V 1 - + V 2 - Measure V I 12 s V I R R 2 22 2 s
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This note was uploaded on 02/20/2010 for the course EE 2315 taught by Professor Staff during the Fall '08 term at UT Arlington.

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Le03 - EE2315 Lecture03 Simple Applications R l A When conductor has uniform cross-section cu 1.67 106 cm al 2.70 106 cm Area A len Metallic

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