le05 - 9/29/2009 E E 2315 Lecture 05 -Mesh Current Analysis...

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9/29/2009 1 E E 2315 Lecture 05 -Mesh Current Analysis Introduction to Mesh Current Method • More direct than branch equations • Fewer equations to solve • Express all variables in terms of mesh Express all variables in terms of mesh currents • Solution is set of mesh currents • Solution completely defines the circuit • Most Convenient Method to Model Magnetic Coupling (E E 2446 Topic) Mesh Current Example 1 (1/2) V s1 V s2 R a R b R c I 1 I 2 + v a -+ v b - + v c - KVL at Mesh 1: KVL at Mesh 2: Using Ohm’s Law: 1 0 s ac Vvv  2 0 cb s vvV     11 1 2 sa c VR I R I I    21 2 2 s cb I I R I  
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9/29/2009 2 Mesh Current Example 1 (2/2) V s1 V s2 R a R b R c I 1 I 2 + v a -+ v b - + v c - Above linear equations can be solved for mesh currents I 1 and I 2 . 1 1 2 2 sa c c sc b c VR R R I R R I      Mesh Current Example 1a (1/2) 120 V 64 V 8 24 I 1 I 2 6 KVL at Mesh 1: KVL at Mesh 2:   11 2 0 120 6 24 II I
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le05 - 9/29/2009 E E 2315 Lecture 05 -Mesh Current Analysis...

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