Slide 13 - Genetics Continued

Slide 13 - Genetics Continued - You can press T to confirm...

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You can press “T” to confirm that you have registered, if you want. Today: Mendelian Genetics
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Midterm examination: Monday, Feb. 22, 6:30 PM, in Hasbrouck 20. Review P, F 1 , F 2 , hybrid cross, homozygous, heterozygous Dominant, recessive, genotype, phenotype Mendel’s “Laws”: Segregation Independent Assortment (for traits on separate chromosomes)
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Example of inheritance that involves sexual reproduction and nudity
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Absence of feathers is a recessive autosomal trait. F = normal feathers f = no feathers
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Example: breed a homozygous normal chicken with a heterozygous chicken. Genotypes: FF and Ff. Both have feathers. Punnett Square: F f F FF Ff F FF Ff FF Ff No mutant phenotype appears. This is how recessive lethal genes are carried in the population.
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Test Cross You have a chicken with feathers. For your breeding program, to get quickly to your desired endproduct, you want to know if it is “FF” or “Ff ” . Do a “Test Cross”. That is-- mate the unknown chicken with a homozygous recessive.
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Test Cross There are 2 possibilities for the unknown chicken with feathers: FF or Ff The test cross possibilities are FF x ff or Ff x ff
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Case 1. The unknown is Ff. This case would be Ff x f f. f f F Ff Ff f f f f f F f f f 50% of the offspring will be featherless.
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The unknown is FF. The test cross is FF x ff. What phenotypes will result?
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Slide 13 - Genetics Continued - You can press T to confirm...

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