Chemistry- Mccord Final

Chemistry- Mccord Final - McCord 10am Please read the...

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Unformatted text preview: McCord 10am Please read the following!! If all goes according to plan this evening, your scores for the final should be available by midnight tonight on Quest. Solu- tions will not be available until 9AM on Sunday morning. Double check your ver- sion number and make sure it (and your UTEID) are bubbled correctly. R = 8 . 314 J/mol K R = 62 . 36 L torr/mol K 1 L atm = 101.325 J 1 F = 96485 C G = H- T S T f = k f m T b = k b m P A = x A P A , pure = cRT ln parenleftbigg P 2 P 1 parenrightbigg = H vap R parenleftbigg 1 T 1- 1 T 2 parenrightbigg ln parenleftbigg K 2 K 1 parenrightbigg = H rxn R parenleftbigg 1 T 1- 1 T 2 parenrightbigg ln parenleftbigg k 2 k 1 parenrightbigg = E a R parenleftbigg 1 T 1- 1 T 2 parenrightbigg G =- nFE G =- RT ln K anode | anode solution || cathode solution | cathode E = E - RT nF ln Q E = E - . 05916 n log Q I t n F = moles ln parenleftbigg [A] [A] parenrightbigg = kt 1 [A]- 1 [A] = kt [A]- [A] = kt Version 208 Final Exam McCord (53575) 2 This print-out should have 52 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points The first order rate constant for A products is 7 . 2 s 1 . If [A] = 2 . 9 M at t = 0, what is the value of [A] at t = 0 . 5 s? 1. 1 . 58478 M 2. . 0158478 M 3. 3 . 96194 10 5 M 4. 1 . 98097 10 5 M 5. . 0792388 M correct Explanation: [A] = 2 . 9 M t = 0 . 5 s k = 7 . 2 s 1 If the reaction is first order, the integrated rate equation is ln parenleftbigg [A] [A] parenrightbigg = ak t ln[ A ]- ln[ A ] = ak t ln[ A ] = ln[ A ]- ak t = ln(2 . 9 M)- (1) ( 7 . 2 s 1 ) (0 . 5 s) =- 2 . 53529 M [ A ] = 0 . 0792388 M 002 10.0 points If you go to the top of a mountain, the amount of carbon dioxide that will dissolve in water should increase compared to sea level. 1. False correct 2. True Explanation: Gas pressures are low at high altitudes. 003 10.0 points What is K sp for Hg 2 Cl 2 , if its molar solu- bility is 5 . 2 10 7 mol / L? 1. 6 . 9 10 9 2. 5 . 6 10 19 correct 3. 5 . 2 10 19 4. 1 . 4 10 21 5. 8 . 3 10 17 6. 0.0053 7. 1 . 7 10 14 Explanation: S = 5 . 2 10 7 mol / L The solubility equilibrium is Hg 2 Cl 2 (s) Hg 2+ 2 (aq) + 2 Cl (aq) [Hg 2+ 2 ] = S = 5 . 2 10 7 mol / L [Cl ] = 2 S = 1 . 04 10 6 mol / L K sp = [Hg 2+ 2 ][Cl ] 2 = (5 . 2 10 7 ) ( 1 . 04 10 6 ) 2 = 5 . 62432 10 19 004 10.0 points Which of the following indicators would be most suitable for the titration of 0.10 M (CH 3 ) 3 N(aq) with 0.10 M HClO 4 (aq)? For trimethyamine, p K b = 4.19....
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Chemistry- Mccord Final - McCord 10am Please read the...

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