Homework_1 - oneal(jo7344 Homework1 Storr(37517 This...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
o’neal (jo7344) – Homework1 – Storr – (37517) 1 This print-out should have 19 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points A rocket initially at rest accelerates at a rate of 70 m / s 2 for 0 . 81 min. What is its speed at the end of this time? Correct answer: 3402 m / s. Explanation: Let : a = 70 m / s 2 and t = 0 . 81 min . v f = v o + a t = a t = (70 m / s 2 ) (0 . 81 min) 60 s 1 min = 3402 m / s . 002 (part 1 of 2) 10.0 points A glacier advances at 6 . 3 × 10 - 6 cm / s. How far will it move in 66000 s? Correct answer: 0 . 4158 cm. Explanation: Let : v = 6 . 3 × 10 - 6 cm / s and t = 66000 s . s = v t = (6 . 3 × 10 - 6 cm / s) (66000 s) = 0 . 4158 cm . 003 (part 2 of 2) 10.0 points How far will it move in 6 . 9 y? Correct answer: 1370 . 87 cm. Explanation: s = v t = (6 . 3 × 10 - 6 cm / s) (6 . 9 y) × 365 d 1 y 24 h 1 d 3600 s 1 h = 1370 . 87 cm . 004 10.0 points The Earth’s radius is about 6380 km. The space shuttle is orbiting about 271.8 km above Earth’s surface. If the average speed of the space shuttle is 28800 km / h, find the time required for it to circle Earth. Correct answer: 1 . 4512 h. Explanation: Let : v avg = 28800 km / h , r Earth = 6380 km , and Δ y = 271 . 8 km . The circumference of the orbit is C = 2 π r orbit , so Δ t = C v avg = 2 π ( r Earth + Δ y ) v avg = 2 π (6380 km + 271 . 8 km) 28800 km / h = 1 . 4512 h . 005 10.0 points A baseball goes from zero to 37 m / s in 0 . 191 s. What is its average acceleration? Correct answer: 193 . 717 m / s 2 . Explanation: Let : v f = 37 m / s , v 0 = 0 m / s , and t = 0 . 191 s .
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
o’neal (jo7344) – Homework1 – Storr – (37517) 2 a = Δ v Δ t = v f - v 0 t = 37 m / s - 0 m / s 0 . 191 s = 193 . 717 m / s 2 006 10.0 points A four-engine jet accelerates down the runway at 3 m / s 2 . If one of the jet engines fails, how much acceleration will the other three produce? Correct answer: 2 . 25 m / s 2 . Explanation: Let : a 0 = 3 m / s 2 . Since four engines produce an acceleration of a , each produces one-fourth of the origi- nal acceleration and three of the engines will produce a = 3 4 a 0 = 3 4 (3 m / s 2 ) = 2 . 25 m / s 2 .
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern